C ++ visual studio内联汇编抓取整数 [英] C++ visual studio inline assembly grabbing integer

问题描述

我遇到的问题是我正在尝试将整数移动到EAX中，这样，



mov eax，5000



我需要一种方法来获取输入，'mov eax，val'。



使用十六进制编辑器查看时，它确实'mov eax，val'但是我需要完成的是字面上移动值，而不是包含值的地址。



我有什么试过：



int val;

cout<< 价值;

cin>> val



mov eax，val

The problem I'm having is I'm trying to move an integer into EAX like so,

mov eax,5000

I would need a way to grab the input, and 'mov eax, val'.

When viewing it with a hex editor, it does 'mov eax, val' BUT what I need to accomplish is literally moving the value, not the address containing the value.

What I have tried:

int val;
cout << "value";
cin >> val

mov eax, val

推荐答案

这样做。

This will do it.

int inputValue; // set from data received from user
__asm {  
   mov eax, inputValue
   
   ... remaining assembler code

}

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