如何将数组中的0值更改为其他值 [英] How to change value of 0 in array to other value

问题描述

当子串值大于0时，如何更改代码，但如果小于或等于0将自动转为值3



我尝试了什么：

  double  rulesfpadouble = 1.45779894373497397E20; 
  String  [] too =  String  .valueOf（rulesfpadouble）.replaceAll（  \\ D， ）。split（ ）; 
  int  [] remainingders =  new   int [too.length]; 
  int  count; 
 
  for （ int  i =  0 ; i< too.length; i ++）
 {
  if （too [i] ==   0）{
 
 remainingders [i] =（（Integer.parseInt（也是） [i]）+ 1）*  3 ）; 
 
} 
  else   if （too [i]！=   0）
 {
 remainingders [i] =（Integer.parseInt （太[i]）％ 2 ）; 
} 
  //   System.out.println（剩余人数：\t+剩余人数[i]）;  
} 
 
  //  系统。 out.println（Arrays.toString（remainingders））;  
 
 str = Arrays.toString（remainingders）.replaceAll（  \\\\ +， ）
 .replace（ ，， ） //  删除逗号 
 .replace（  [， ） //  删除右括号 
 .replace（  ]， ） //  删除左括号 
 .trim（）;  //  从部分初始化的数组中删除尾随空格 
 
 System.out.println （ 下一代规则：\t + str）; 
 

解决方案

我现在指的是你的例子。在你的例子中，你测试的数字是

 double rulesfpadouble = 1.45779894373497397E20; 

所以你的变量看起来像

 = [1,4,5,7,7,9,8,9,4,3,7,3,9,2,0]; 

所以我猜你希望你的余数是：

余数= [1,0,1,1,1,1,0,1,0,1,1,1,0 ，1,1,1,1,0,3]; 

您可以使用以下代码实现此目的（我稍微简化了您的代码）：

 double rulesfpadouble = 1.45779894373497397E20; 
 String [] too = String.valueOf（rulesfpadouble）.replaceAll（\\ D，）。split（）; 
 int [] remainingders = new int [too.length]; 
 for（int i = 0; i< too.length; i ++）{
 int numberToTest = Integer.parseInt（too [i]）; 
 if（numberToTest == 0）{
 remainingders [i] = 3; 
} else {
 remainingders [i] =（Integer.parseInt（too [i]）％2）; 
} 
} 

在您的代码中，零测试失败。那是因为你使用了 String.valueOf（）方法。如果你想直接测试字符串，你必须使用来[i] .equals（0）。

希望这会有所帮助。

How to change code when the substring value more than 0 will be modulo 2 but if less or equal than 0 will automatically turn to value 3

What I have tried:

double rulesfpadouble =1.45779894373497397E20;
   String[] too = String.valueOf(rulesfpadouble).replaceAll("\\D", "").split("");
              int[] remainders = new int[too.length];
            int count;

               for (int i = 0; i < too.length; i++)
               {
                   if(too[i]=="0"){

                   remainders[i] = ((Integer.parseInt(too[i])+1)*3);

                   }
                   else if (too[i]!="0")
                   {
                 remainders[i] = (Integer.parseInt(too[i]) % 2);
                   }
              //System.out.println("Remainders :\t"+ remainders[i]);
               }

              //System.out.println(Arrays.toString(remainders));

               str = Arrays.toString(remainders).replaceAll("\\s+","")
              .replace(",", "")  //remove the commas
              .replace("[", "")  //remove the right bracket
              .replace("]", "")  //remove the left bracket
              .trim();           //remove trailing spaces from partially initialized array

            System.out.println("Rule of next gen:\t"+ str);

解决方案

I'm referring to your example now.In your example the number you test is

double rulesfpadouble =1.45779894373497397E20;

so your variable looks like

too = [1, 4, 5, 7, 7, 9, 8, 9, 4, 3, 7, 3, 9, 2, 0];

So I guess you expect your remainder to be:

remainder = [1, 0, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 0, 3];

You can achive this with the following code (I smiplified your code a little bit):

double rulesfpadouble = 1.45779894373497397E20;
String[] too = String.valueOf(rulesfpadouble).replaceAll("\\D", "").split("");
int[] remainders = new int[too.length];
for (int i = 0; i < too.length; i++) {
    int numberToTest = Integer.parseInt(too[i]);
    if (numberToTest == 0) {
	remainders[i] = 3;
    } else {
	remainders[i] = (Integer.parseInt(too[i]) % 2);
    }
}

In your code the test for zero failed. That is because you yoused the String.valueOf() method. If you want to test the string directly you must use too[i].equals("0").
Hope this helps.

这篇关于如何将数组中的0值更改为其他值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！