如何使用PHP将select选项保存到数据库中？ [英] How can I save select option into database using PHP?
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问题描述
我收到错误说：
错误：INSERT INTO dbstation（From，To，Date）值（'fAG'，'tkulim'，'2018-09-30'）你有错误你的SQL语法;检查与您的MariaDB服务器版本对应的手册，以便在第1行的From，To，Date值（'fAG'，'tkulim'，'2018-09-30'）附近使用正确的语法
你能帮我解决这个问题吗？提前谢谢。
这是我的HTML代码：
< html>
< head>
< title>主菜单< / title>
< link rel =stylesheettype =text / csshref =menu_style.css>
< link rel =stylesheettype =text / csshref =Datepicker.css>
< / head>
< body>
< div class =menu>
<！ - < div class =btn> - >
< a href =main.html>< button class =btn>预订< / button>< / a>
< a href =history.html>< button class =btn>历史< / button>< / a>
< a href =reservation.html>< button class =btn>预订< / button>< / a>
< a href =trainpay.html>< button class =btn> TrainPay< / button>< / a>
< a href =reservation.html>< button class =btn>更新个人资料< / button>< / a>
< br>< br>< br>
<！ - < / div> - >
<！ - < div class =station> - >
< form align =centermethod =postaction =station.php>
来自
< select name =from>
< option value =fkluang> Kluang，Johor< / option>
< option value =fAG> Alor Gajah，Melaka< / option>
< option value =fSenawang> Senawang，NS< / option>
< option value =fKL> KL Sentral，KL< / option>
< option value =fipoh> Ipoh，Perak< / option>
< option value =fkulim> Kulim，Kedah< / option>
< option value =fkangar> Kangar，Perlis< / option>
< / select>
到
< select name =to>
< option value =tkluang> Kluang，Johor< / option>
< option value =tAG> Alor Gajah，Melaka< / option>
< option value =tSenawang> Senawang，NS< / option>
< option value =tKL> KL Sentral，KL< / option>
< option value =tipoh> Ipoh，Perak< / option>
< option value =tkulim> Kulim，Kedah< / option>
< option value =tkangar> Kangar，Perlis< / option>
< / select>
< label>日期：< / label>
< input name =dateetype =date/>
<！ - 按钮选择时间表 - >
< a href =schedule.html>< button align =rightclass =buttonname =go> go< / button>< / a>
< / form>
< / div>
< div class =tr>
< img id ='train-route'
src =train_route.jpg
alt =
width =900
height =450 />
< / div>
< / body>
< / html>
我尝试过：
<？php
$ from = filter_input（INPUT_POST，'from'）;
$ to = filter_input（INPUT_POST，'to'）;
$ datee = filter_input（INPUT_POST，'datee'）;
if（！empty（$ from））{
if（！empty（$ to））{
if（！empty（$ datee））{
$ host =localhost;
$ dbusername =root;
$ dbpassword =;
$ dbname =station;
//创建连接
$ conn = new mysqli（$ host，$ dbusername，$ dbpassword，$ dbname）;
if（mysqli_connect_error（））
{
die（'Connect Error（'。mysqli_connect_errno（）。'）'。mysqli_connect_error（））;
}
else
{
$ sql =INSERT INTO dbstation（From，To，Date）值（'$ from'，'$ to'，' $日期E'）;
if（$ conn-> query（$ sql））
{
echo成功插入新记录;
}
else
{
echo错误：。$ sql。
。$ conn->错误;
}
$ conn-> close（）;
}
}
其他
{
// echo日期不应为空;
// die（）;
}
}
else {
// echo密码不应为空;
// die（）;
}
}
else {
// echo用户名不应为空;
// die（）;
}
？>
解决方案
from = filter_input（INPUT_POST，'from'）;
to = filter_input（INPUT_POST，'to'）;
datee = filter_input（INPUT_POST，'datee'）;
if（！empty（
I got an error says:
Error: INSERT INTO dbstation(From, To, Date) values('fAG', 'tkulim', '2018-09-30') You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'From, To, Date) values('fAG', 'tkulim', '2018-09-30')' at line 1
Can you help me to solve this problem? thanks in advance.
This is my html code:
<html>
<head>
<title>Main Menu</title>
<link rel="stylesheet" type="text/css" href="menu_style.css">
<link rel="stylesheet" type="text/css" href="Datepicker.css">
</head>
<body>
<div class="menu">
<!-- <div class="btn"> -->
<a href="main.html"><button class="btn">Booking</button></a>
<a href="history.html"><button class="btn">History</button></a>
<a href="reservation.html"><button class="btn">Reservation</button></a>
<a href="trainpay.html"><button class="btn">TrainPay</button></a>
<a href="reservation.html"><button class="btn">Update profile</button></a>
<br><br><br>
<!-- </div> -->
<!-- <div class="station"> -->
<form align="center" method="post" action="station.php">
From
<select name="from">
<option value="fkluang">Kluang, Johor</option>
<option value="fAG">Alor Gajah, Melaka</option>
<option value="fSenawang">Senawang, NS</option>
<option value="fKL">KL Sentral, KL</option>
<option value="fipoh">Ipoh, Perak</option>
<option value="fkulim">Kulim, Kedah</option>
<option value="fkangar">Kangar, Perlis</option>
</select>
To
<select name="to">
<option value="tkluang">Kluang, Johor</option>
<option value="tAG">Alor Gajah, Melaka</option>
<option value="tSenawang">Senawang, NS</option>
<option value="tKL">KL Sentral, KL</option>
<option value="tipoh">Ipoh, Perak</option>
<option value="tkulim">Kulim, Kedah</option>
<option value="tkangar">Kangar, Perlis</option>
</select>
<label>Date: </label>
<input name="datee" type="date"/>
<!-- Button to choose schedule -->
<a href="schedule.html"><button align="right" class="button" name="go">go</button></a>
</form>
</div>
<div class="tr">
<img id='train-route'
src="train_route.jpg"
alt=""
width="900"
height="450" />
</div>
</body>
</html>
What I have tried:
<?php
$from = filter_input(INPUT_POST, 'from');
$to = filter_input(INPUT_POST, 'to');
$datee = filter_input(INPUT_POST, 'datee');
if (!empty($from)){
if (!empty($to)){
if (!empty($datee)){
$host = "localhost";
$dbusername = "root";
$dbpassword = "";
$dbname = "station";
// Create connection
$conn = new mysqli ($host, $dbusername, $dbpassword, $dbname);
if(mysqli_connect_error())
{
die('Connect Error('.mysqli_connect_errno().')'.mysqli_connect_error());
}
else
{
$sql = "INSERT INTO dbstation(From, To, Date) values('$from', '$to', '$datee')";
if($conn->query($sql))
{
echo "New record is inserted successfully";
}
else
{
echo "Error: ".$sql."
".$conn->error;
}
$conn->close();
}
}
else
{
// echo "Date should not be empty";
// die();
}
}
else{
// echo "Password should not be empty";
// die();
}
}
else{
// echo "Username should not be empty";
// die();
}
?> 解决方案
from = filter_input(INPUT_POST, 'from');
to = filter_input(INPUT_POST, 'to');
datee = filter_input(INPUT_POST, 'datee'); if (!empty(
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