如何在我的变速器必须不是角色的情况下放入 [英] How do I put in while condition that my viariable must be not a character

问题描述

你好;

我有一些小麻烦找到一种方法来处理我的条件下我的变量int必须不是从请求的输入中获取的字符在我的周期之前。

虽然循环用于检查输入中写入的变量是否与算法所需的条件不匹配。



我尝试过：



这里是一个代码示例：

#include< stdio。 h>



int main（）{

int n;

scanf（％d，& ; n）;

while（n< = - 1）{

printf（不正确。写一个正整数。）;

scanf（％d，& n）;

}





返回0;

}



这适用于数字，但如果在输入中我写了一个像g这样的字符，它就会松开，我必须控制+ c，阻止它。

Hello;
I am having some little troubles finding out a way to put under my while condition the fact that my variable which is an "int" must be not a character took from an input requested before my while cycle.
While cycle is used to check if the variable wrote in input doesnt match with conditions i need for the algorithm.

What I have tried:

here is an example of code:
#include <stdio.h>

int main(){
int n;
scanf("%d", &n);
while(n<=-1 ){
printf("Incorrect. Write a positive integer.");
scanf("%d", &n);
}


return 0;
}

This is working for numbers, but if in input i write a character like "g" it loopes and i must control+c, blocking it.

推荐答案

你标记了这个C＃，但它我显然是C或C ++。

然而，这是一个非常简单的问题需要循环解决：

You tagged this C#, but it is clearly C or C++.
However, this is quite a simple problem to resolve with a loop:

int n;
while (scanf("%d", &n) == 0 || n < 0) // if no values captured, or the result is negative
{
    printf("Incorrect. Write a positive integer.");
    fseek(stdin,0,SEEK_END);
}

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