Graphics.drawline 8388608限制值 [英] Graphics.drawline 8388608 limit value

问题描述

你好大家

当graphics.drawLine（笔（x1，y1，x2，y2）;

X1，y1值或x2，y2值大于8388608 ，绘制反向线，如何解决？



我尝试过：



int y = 8388607;

gfx.DrawLine（new Pen（Color.Red，1），100,100,100，y）;

y = 8388608;

gfx.DrawLine（新笔（Color.Blue，1），110,100,110，y）;

hello everybody
When the graphics.drawLine (pen (x1, y1, x2, y2);
X1, y1 values or x2, y2 values greater than 8388608, draw inverse line, how to solve?

What I have tried:

int y = 8388607;
gfx.DrawLine(new Pen(Color.Red, 1), 100, 100, 100, y);
y = 8388608;
gfx.DrawLine(new Pen(Color.Blue, 1), 110, 100, 110, y);

推荐答案

简单： GDI使用的坐标系是24位：并且十六进制中的8288607是7FFFFF - 一个大于那个变为负数，因为位23然后被设置。



不，你除了停止尝试绘制荒谬的大坐标之外，我们无能为力！对位图的大小有限制： C＃.NET Bitmap的最大分辨率是多少？ - 堆栈溢出 [ ^ ]

Simple: the coordinate system GDI uses is 24 bit: and 8288607 in hex is 7FFFFF - one greater than that becomes a negative number as bit 23 is then set.

No, you can't do anything about that, other than stop trying to draw absurdly large coordinates! There are restrictions on how large a bitmap can be anyway: What is the maximum resolution of C# .NET Bitmap? - Stack Overflow[^]

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