程序要求输入，然后不显示任何输出。 [英] Program is asking for the input and then do not shows any output.

问题描述

#include<stdio.h>
main()
{
	int scores[3], sum;
	float avg;
	printf("enter the value for scores\n");
	scanf("%d\n %d\n %d\n",&scores[0],&scores[1],&scores[2]);
	sum=scores[0]+scores[1]+scores[2];
	avg=sum/3;
	printf("The sum is :%d\n The avg is :%f\n",sum,avg);
	system("pause");
}

真正的计划是：

The real program is:

#include<stdio.h>
main()
{
int scores[3],sum;
float avg;
printf("Enter Score 1 : ");
scanf("%d",&scores[0]);
printf("Enter Score 2 : ");
scanf("%d",&scores[1]);
printf("Enter Score 3 : ");
scanf("%d",&scores[2]);
sum=scores[0]+scores[1]+scores[2];
avg=sum/3;
printf("Sum is = %d\nAverage = %f\n",sum,avg);
system("pause");

我尝试过：



问题很大，我试图修剪它但输入3个输入时没有显示输出。

What I have tried:

The problem is big and I tried to trim it but it is showing no output when I enter 3 inputs.

推荐答案

它适用于我：

It works fine for me:

enter the value for scores
10
20
30
The sum is :60
 The avg is :20
Sum is = 60
Average = 20

并且

Enter Score 1 : 10
Enter Score 2 : 20
Enter Score 3 : 30
Sum is = 60
Average = 20

检查您是否正在运行正确的可执行文件...并尝试摆脱系统（暂停）行。

#include<stdio.h>
int main(void)
{
	int scores[3], sum;
	float avg;
	printf("enter the value for scores\n");
	scanf("%d%d%d",&scores[0],&scores[1],&scores[2]);
	sum=scores[0]+scores[1]+scores[2];
	avg=sum/3.0;
	printf("The sum is :%d\n The avg is :%f\n",sum,avg);
	return 0;
}

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