检查我的'xdateago'函数的编码算法 [英] Check my coding algorithm of 'xdateago' function
问题描述
功能 xDateAgo( ByVal D 作为 日期,可选 ByVal StatusWord 作为 字符串 = 创建)作为 字符串
Dim Expr $ = StatusWord + at
昏暗小时,分钟,秒,天,周,月,年 As 整数
Dim OldMonthDays,CurrentMonthDays,PlusDays 正如 整数
Dim 值()作为 String = { , , , }
Dim x%= 0
6:年= 0
Months = 0
OldMonthDays = DateTime.DaysInMonth(D.Year,D.Month) - DatePart(DateInterval.Day,D)
CurrentMonthDays = DatePart( DateInterval.Day,Now)
如果 Now.Year = D.Year 那么
选择 案例 D.Month
案例 = Now.Month
PlusDays = CurrentMonthDays - DatePart(DateInterval.Day,D)
案例 < Now.Month
Months = DateDiff(DateInterval.Month,DateSerial(D.Year,D.Month,DateTime.DaysInMonth(D.Year,D.Month)),DateSerial(Now.Year,Now.Month,< span class =code-digit> 1 ))
如果 CurrentMonthDays> = DatePart(DateInterval.Day,D)然后
PlusDays =(CurrentMonthDays) - DatePart(DateInterval.Day,D)
ElseIf OldMonthDays + CurrentMonthDays> = DateTime.DaysInMonth(D.Year,D.Month)然后
PlusDays =(OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
其他
PlusDays = OldMonthDays + CurrentMonthDays
结束 < span class =code-keyword>如果
结束 选择
ElseIf Now.Year > D.Year 然后
年= DateDiff(DateInterval.Year,D,Now)
Months = DateDiff(DateInterval.Month,DateSerial(D。 Year,D.Month,DateTime.DaysInMonth(D.Year,D.Month)),DateSerial(Now.Year,Now.Month, 1 ))
如果月份> =(年* 12 )那么
月份=月份 - (年* 12 )
结束 如果
如果月/ 12 < =年然后
年=年 - 月/ 12
< span class =code-keyword>结束 如果
PlusDays = CurrentMonthDays
如果 CurrentMonthDays> = DatePart(DateInterval.Day,D)那么
PlusDays =(CurrentMonthDays ) - DatePart(DateInterval.Day,D)
ElseIf OldMonthDays + CurrentMonthDays> = DateTime.DaysInMonth(D.Year,D.Month)然后
PlusDays =(OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day,D)
Else
PlusDays = OldMonthDays + CurrentMonthDays
Months - = 1
结束 如果
结束 如果
周=(PlusDays \ 7 )
天= 如果(PlusDays> ; = 7 ,PlusDays Mod 7 ,PlusDays )
如果年> 0 然后
值( 0 )= 字符串 .Format( {0}年份{1},年,如果(年>&span; 1 , s, ))
结束 如果
5: 如果 CBool (月份> 0 ) 然后
值( 1 )= String .Format( {0}月{1},月份,如果跨度>(月> 1 , s, ))
结束 < span class =code-keyword>如果
如果 CBool (周) > 0 )然后
值( 2 )= 字符串 .Format( { 0}周{1},周,如果(周> 1 ,< span class =code-string> s, ))
结束 如果
' {需要x时间以前...
Dim T1,T2,T3 As TimeSpan
T1 = D.TimeOfDay
T2 = Now.TimeOfDay
Hours =(( 24 - T1.Hours)+ T2.Hours) - 1
分钟=(( 60 - T1.Minutes)+ T2.Minutes) - 1
秒=(( 60 - T1.Seconds)+ T2.Seconds)
T3 = 新 TimeSpan(小时,分钟,秒)
如果 T2< T1.Add(新 TimeSpan( 0 , 0 , - 1))然后
天 - = 1
结束 如果
Hours = T3.Hours
Minutes = T3.Minutes
秒= T3.Seconds
' ...}
如果 CBool (天>&span; 0 )然后
值( 3 )= 字符串。格式( {0}日{1},天,如果(天>&span; 1 , s, ))
结束 如果
对于 每个 v 作为 字符串 在值
如果 v.Length> 0 然后
Expr + = String .Format( If (x = 0 , {0}, {1 } {0}),v, ,)
x + = 1
结束 如果
下一步
Expr + = 字符串 .Format( {1} {0},格式(TimeSerial(小时,分钟,秒), HH:mm:ss),_
如果(是啊rs> 0 或月份> 0 或天> 0 或周> 0 , 和, ))
Expr + = ago
返回 Expr
结束 功能
< b>我尝试了什么:
请检查我的编码算法以使更好
< blockquote> = StatusWord + at 这篇关于检查我的'xdateago'函数的编码算法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
昏暗小时,分钟,秒,天,周,月,年作为 整数
Dim OldMonthDays,CurrentMonthDays,PlusDays As 整数
Dim 值()正如 字符串 = { , , < span class =code-string>, }
Dim x%= 0
6:年= 0
Months = 0
OldMonthDays = DateTime.DaysInMonth(D.Year,D.Month) - DatePart(DateInterval。 Day,D)
CurrentMonthDays = DatePart(DateInterval.Day,Now)
If Now.Year = D.Year 然后
选择
Case = Now.Month
PlusDays = CurrentMonthDays - DatePart(DateInterval.Day,D)
Case 是< Now.Month
Months = DateDiff(DateInterval.Month,DateSerial(D.Year,D.Month,DateTime.DaysInMonth(D.Year,D.Month)),DateSerial(Now.Year,Now.Month,< span class =code-digit> 1 ))
如果 CurrentMonthDays> = DatePart(DateInterval.Day,D)然后
PlusDays =(CurrentMonthDays) - DatePart(DateInterval.Day,D)
ElseIf OldMonthDays + CurrentMonthDays> = DateTime.DaysInMonth(D.Year,D.Month)然后
PlusDays =(OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
其他
PlusDays = OldMonthDays + CurrentMonthDays
结束 < span class =code-keyword>如果
结束 选择
ElseIf Now.Year > D.Year 然后
年= DateDiff(DateInterval.Year,D,Now)
Months = DateDiff(DateInterval.Month,DateSerial(D。 Year,D.Month,DateTime.DaysInMonth(D.Year,D.Month)),DateSerial(Now.Year,Now.Month, 1 ))
如果月份> =(年* 12 )那么
月份=月份 - (年* 12 )
结束 如果
如果月/ 12 < =年然后
年=年 - 月/ 12
< span class =code-keyword>结束 如果
PlusDays = CurrentMonthDays
如果 CurrentMonthDays> = DatePart(DateInterval.Day,D)那么
PlusDays =(CurrentMonthDays ) - DatePart(DateInterval.Day,D)
ElseIf OldMonthDays + CurrentMonthDays> = DateTime.DaysInMonth(D.Year,D.Month)然后
PlusDays =(OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day,D)
Else
PlusDays = OldMonthDays + CurrentMonthDays
Months - = 1
结束 如果
结束 如果
周=(PlusDays \ 7 )
天= 如果(PlusDays> ; = 7 ,PlusDays Mod 7 ,PlusDays )
如果年> 0 然后
值( 0 )= 字符串 .Format( {0}年份{1},年,如果(年>&span; 1 , s, ))
结束 如果
5: 如果 CBool (月份> 0 ) 然后
值( 1 )= String .Format( {0}月{1},月份,如果跨度>(月> 1 , s, ))
结束 < span class =code-keyword>如果
如果 CBool (周) > 0 )然后
值( 2 )= 字符串 .Format( { 0}周{1},周,如果(周> 1 ,< span class =code-string> s, ))
结束 如果
'
Dim T1,T2,T3 As TimeSpan
T1 = D.TimeOfDay
T2 = Now.TimeOfDay
Hours =(( 24 - T1.Hours)+ T2.Hours) - 1
分钟=(( 60 - T1.Minutes)+ T2.Minutes) - 1
秒=(( 60 - T1.Seconds)+ T2.Seconds)
T3 = 新 TimeSpan(小时,分钟,秒)
如果 T2< T1.Add(新 TimeSpan( 0 , 0 , - 1))然后
天 - = 1
结束 如果
Hours = T3.Hours
Minutes = T3.Minutes
秒= T3.Seconds
' ...}
如果 CBool (天>&span; 0 )然后
值( 3 )= 字符串。格式( {0}日{1},天,如果(天>&span; 1 , s, ))
结束 如果
对于 每个 v 作为 字符串 在值
如果 v.Length> 0 然后
Expr + = String .Format( If (x = 0 , {0}, {1 } {0}),v, ,)
x + = 1
结束 如果
下一步
Expr + = 字符串 .Format( {1} {0},格式(TimeSerial(小时,分钟,秒), HH:mm:ss),_
如果(是啊rs> 0 或月份> 0 或天> 0 或周> 0 , 和, ))
Expr + = ago
返回 Expr
结束 功能
< b>我尝试了什么:
请检查我的编码算法以使其更好
否。我们不做你的功课:这是有原因的。它就是为了让你思考你被告知的事情,并试着理解它。它也在那里,以便您的导师可以识别您身体虚弱的区域,并将更多的注意力集中在补救措施上。
亲自尝试,你可能会发现它不是和你想的一样困难!
如果遇到具体问题,请询问相关问题,我们会尽力提供帮助。但我们不打算为你做这一切!
Function xDateAgo(ByVal D As Date, Optional ByVal StatusWord As String = "Created") As String
Dim Expr$ = StatusWord + " at "
Dim Hours, Minutes, Seconds, Days, Weeks, Months, Years As Integer
Dim OldMonthDays, CurrentMonthDays, PlusDays As Integer
Dim Value() As String = {"", "", "", ""}
Dim x% = 0
6: Years = 0
Months = 0
OldMonthDays = DateTime.DaysInMonth(D.Year, D.Month) - DatePart(DateInterval.Day, D)
CurrentMonthDays = DatePart(DateInterval.Day, Now)
If Now.Year = D.Year Then
Select Case D.Month
Case Is = Now.Month
PlusDays = CurrentMonthDays - DatePart(DateInterval.Day, D)
Case Is < Now.Month
Months = DateDiff(DateInterval.Month, DateSerial(D.Year, D.Month, DateTime.DaysInMonth(D.Year, D.Month)), DateSerial(Now.Year, Now.Month, 1))
If CurrentMonthDays >= DatePart(DateInterval.Day, D) Then
PlusDays = (CurrentMonthDays) - DatePart(DateInterval.Day, D)
ElseIf OldMonthDays + CurrentMonthDays >= DateTime.DaysInMonth(D.Year, D.Month) Then
PlusDays = (OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
Else
PlusDays = OldMonthDays + CurrentMonthDays
End If
End Select
ElseIf Now.Year > D.Year Then
Years = DateDiff(DateInterval.Year, D, Now)
Months = DateDiff(DateInterval.Month, DateSerial(D.Year, D.Month, DateTime.DaysInMonth(D.Year, D.Month)), DateSerial(Now.Year, Now.Month, 1))
If Months >= (Years * 12) Then
Months = Months - (Years * 12)
End If
If Months / 12 <= Years Then
Years = Years - Months / 12
End If
PlusDays = CurrentMonthDays
If CurrentMonthDays >= DatePart(DateInterval.Day, D) Then
PlusDays = (CurrentMonthDays) - DatePart(DateInterval.Day, D)
ElseIf OldMonthDays + CurrentMonthDays >= DateTime.DaysInMonth(D.Year, D.Month) Then
PlusDays = (OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
Else
PlusDays = OldMonthDays + CurrentMonthDays
Months -= 1
End If
End If
Weeks = (PlusDays \ 7)
Days = If(PlusDays >= 7, PlusDays Mod 7, PlusDays)
If Years > 0 Then
Value(0) = String.Format("{0} Year{1}", Years, If(Years > 1, "s", ""))
End If
5: If CBool(Months > 0) Then
Value(1) = String.Format("{0} Month{1}", Months, If(Months > 1, "s", ""))
End If
If CBool(Weeks > 0) Then
Value(2) = String.Format("{0} Week{1}", Weeks, If(Weeks > 1, "s", ""))
End If
' { to take x Time ago...
Dim T1, T2, T3 As TimeSpan
T1 = D.TimeOfDay
T2 = Now.TimeOfDay
Hours = ((24 - T1.Hours) + T2.Hours) - 1
Minutes = ((60 - T1.Minutes) + T2.Minutes) - 1
Seconds = ((60 - T1.Seconds) + T2.Seconds)
T3 = New TimeSpan(Hours, Minutes, Seconds)
If T2 < T1.Add(New TimeSpan(0, 0, -1)) Then
Days -= 1
End If
Hours = T3.Hours
Minutes = T3.Minutes
Seconds = T3.Seconds
' ...}
If CBool(Days > 0) Then
Value(3) = String.Format("{0} Day{1}", Days, If(Days > 1, "s", ""))
End If
For Each v As String In Value
If v.Length > 0 Then
Expr += String.Format(If(x = 0, "{0}", "{1}{0}"), v, ", ")
x += 1
End If
Next
Expr += String.Format("{1}{0}", Format(TimeSerial(Hours, Minutes, Seconds), "HH:mm:ss"), _
If(Years > 0 Or Months > 0 Or Days > 0 Or Weeks > 0, " and ", ""))
Expr += " ago"
Return Expr
End Function
What I have tried:
Please Check my Coding algorithm to make Better= StatusWord + " at "
Dim Hours, Minutes, Seconds, Days, Weeks, Months, Years As Integer
Dim OldMonthDays, CurrentMonthDays, PlusDays As Integer
Dim Value() As String = {"", "", "", ""}
Dim x% = 0
6: Years = 0
Months = 0
OldMonthDays = DateTime.DaysInMonth(D.Year, D.Month) - DatePart(DateInterval.Day, D)
CurrentMonthDays = DatePart(DateInterval.Day, Now)
If Now.Year = D.Year Then
Select Case D.Month
Case Is = Now.Month
PlusDays = CurrentMonthDays - DatePart(DateInterval.Day, D)
Case Is < Now.Month
Months = DateDiff(DateInterval.Month, DateSerial(D.Year, D.Month, DateTime.DaysInMonth(D.Year, D.Month)), DateSerial(Now.Year, Now.Month, 1))
If CurrentMonthDays >= DatePart(DateInterval.Day, D) Then
PlusDays = (CurrentMonthDays) - DatePart(DateInterval.Day, D)
ElseIf OldMonthDays + CurrentMonthDays >= DateTime.DaysInMonth(D.Year, D.Month) Then
PlusDays = (OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
Else
PlusDays = OldMonthDays + CurrentMonthDays
End If
End Select
ElseIf Now.Year > D.Year Then
Years = DateDiff(DateInterval.Year, D, Now)
Months = DateDiff(DateInterval.Month, DateSerial(D.Year, D.Month, DateTime.DaysInMonth(D.Year, D.Month)), DateSerial(Now.Year, Now.Month, 1))
If Months >= (Years * 12) Then
Months = Months - (Years * 12)
End If
If Months / 12 <= Years Then
Years = Years - Months / 12
End If
PlusDays = CurrentMonthDays
If CurrentMonthDays >= DatePart(DateInterval.Day, D) Then
PlusDays = (CurrentMonthDays) - DatePart(DateInterval.Day, D)
ElseIf OldMonthDays + CurrentMonthDays >= DateTime.DaysInMonth(D.Year, D.Month) Then
PlusDays = (OldMonthDays + CurrentMonthDays) - DatePart(DateInterval.Day, D)
Else
PlusDays = OldMonthDays + CurrentMonthDays
Months -= 1
End If
End If
Weeks = (PlusDays \ 7)
Days = If(PlusDays >= 7, PlusDays Mod 7, PlusDays)
If Years > 0 Then
Value(0) = String.Format("{0} Year{1}", Years, If(Years > 1, "s", ""))
End If
5: If CBool(Months > 0) Then
Value(1) = String.Format("{0} Month{1}", Months, If(Months > 1, "s", ""))
End If
If CBool(Weeks > 0) Then
Value(2) = String.Format("{0} Week{1}", Weeks, If(Weeks > 1, "s", ""))
End If
' { to take x Time ago...
Dim T1, T2, T3 As TimeSpan
T1 = D.TimeOfDay
T2 = Now.TimeOfDay
Hours = ((24 - T1.Hours) + T2.Hours) - 1
Minutes = ((60 - T1.Minutes) + T2.Minutes) - 1
Seconds = ((60 - T1.Seconds) + T2.Seconds)
T3 = New TimeSpan(Hours, Minutes, Seconds)
If T2 < T1.Add(New TimeSpan(0, 0, -1)) Then
Days -= 1
End If
Hours = T3.Hours
Minutes = T3.Minutes
Seconds = T3.Seconds
' ...}
If CBool(Days > 0) Then
Value(3) = String.Format("{0} Day{1}", Days, If(Days > 1, "s", ""))
End If
For Each v As String In Value
If v.Length > 0 Then
Expr += String.Format(If(x = 0, "{0}", "{1}{0}"), v, ", ")
x += 1
End If
Next
Expr += String.Format("{1}{0}", Format(TimeSerial(Hours, Minutes, Seconds), "HH:mm:ss"), _
If(Years > 0 Or Months > 0 Or Days > 0 Or Weeks > 0, " and ", ""))
Expr += " ago"
Return Expr
End Function
What I have tried:
Please Check my Coding algorithm to make BetterNo. We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.
Try it yourself, you may find it is not as difficult as you think!
If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!