三元运算符错误 [英] Ternary operator error

问题描述

#include< stdio.h>

int main（）

{

int b，i = 5;

i == 5？b = 2：b = 4;

printf（％d，b）;

返回0;

}



语法错误：需要左值



我尝试过：



使用括号（b = 2）和& （B = 4）。我在互联网上找到了答案。但我不知道原因。请告诉我它的原因。
谢谢。

#include <stdio.h>
int main()
{
int b,i=5;
i==5?b=2:b=4;
printf ("%d",b);
return 0;
}

Syntax error: lvalue required

What I have tried:

The issue gets resolved on using brackets (b=2) & (b=4). I found the answer on internet. But i don't know the reason. Please tell me the reason for it.
Thanks.

推荐答案

运算符优先级是问题：

Operator precedence is the problem:

i == 5 ? (b = 2) : (b = 4);

但是写的非常糟糕，几乎没有任何用处。

相反，试试这个：

But that is very badly written, and does little of any use.
Instead, try this:

b = i == 5 ? 2 : 4;

可以更容易地做同样的事情！

which does the same thing by a lot more readably!

这篇关于三元运算符错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！