TestCafe - 如何在不失败测试的情况下检查Web元素是否存在？ [英] TestCafe - How to check if a web element exists or does not exist without failing the test?

问题描述

我正在尝试编写一个脚本，需要根据CSS选择器找到的特定浏览器对象是否存在来调整其工作流行为。

I'm trying to write a script that needs to adapt it's workflow behavior depending on whether a particular browser object found by CSS selector exists or does not exist.

我不想使用document.getElementByID方法，因为这在技术上不是一个CSS选择器，我们的整个企业都是在CSS选择器上标准化的，所以除了CSS选择器以外的任何东西都不会超过我们的代码审查过程无论如何。

I do not want to use a document.getElementByID method as this is not technically a CSS selector, and our entire enterprise is standardized on CSS selector so anything that walks the DOM other then a CSS selector won't make it past our code review process anyway.

var thing = await things.thingSelector(thingName);
if (await t.expect(thing.exists).notOk()) {
   await t.click(things.OpenThing(thingName));
} else {
   return false;
}
return true;

其中thingSelector是：

Where thingSelector is:

const thingSelector = name =>
  Selector('p.thing-header-title span')
    .withText(name)
    .parent('div.thing');

OpenThing在哪里：

Where OpenThing is:

const OpenThing = name =>
    thingSelector(name)
        .find('a.thing-footer-item')
        .withText('Open');

如果对象不在那里我需要能够继续执行并且我正在检查它存在，或者如果对象在那里并且我正在检查它是否存在，以及对象不在那里并且它不存在且对象不存在且我正在检查它不存在的情况。

I need to be able to continue execution if the object is not there and I'm checking that it exists, or if the object is there and I'm checking that it does not exist, and also the cases where the object is not there and it does not exist and the object is not there and I'm checking that it does not exist.

在所有情况下，我仍然需要继续工作流程。

In all cases I still need to proceed with the workflow.

我已尝试过双方逻辑硬币：

I've tried both sides of the logic coin:

if (!await t.expect(thing.exists).ok())

和

if (await t.expect(thing.exists).notOk())

如果上述之一没有如果在一种情况下失败，它将在另一种情况下失败，而另一种情况将在第一种没有失败的情况下失败。我需要一些能给我逻辑的东西，但不会让脚本执行失败，并且仍允许我返回True或False，具体取决于对象是否存在。

If one of the above doesn't fail in one scenario it will fail in the other, and the other one will fail in the scenario that the first one didn't fail. I need something that will give me the logic, but not ever fail the script execution and still allow me to return either True or False depending on if the object is present or not present.

提前感谢您帮助我解决这个问题，同时也学习和发展我的Javascript技能！

Thank you in advance for helping me to solve this problem, and also to learn and grow in my Javascript skills!

推荐答案

您可以通过以下方式检查 if 条件中的async exists 属性：

You can check the async exists property in the if condition in the following way:

if(await things.thingSelector(thingName).exists) {
    // do something 
} 

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