如何仅在使用while循环（无阵列）的情况下在C框中打印框 [英] How do I print boxes inside of boxes in C whilst only using while loops (without arrays)

问题描述

只需要使用while循环和if语句来解决这个问题所需的正确逻辑需要一些直觉





我需要能够按照这样的标题中所述打印盒子内的盒子。



我尝试过：

Need some intuition on the correct logic needed to solve this problem with only using while loops and if statements


I need to be able to print boxes inside of boxes as stated in the title like this.

What I have tried:

#include <stdio.h>


int main(void) {

    int boxes;
        
    printf("How many boxes: ");
    scanf("%d", &boxes);
    
    
    int boxSide = boxes *3 + (boxes - 1);
    int i;
    int j;



        int row = 0;   

            while (row < boxSide) {
            
                int column = 0;
                
                while (column < boxSide) {

                    if ((row % 2 == 0) && (column % 2 ==0))  {
                    
                      printf("#");
                    
                    }

                    else if (row == 0 || row == boxSide-1 || column == 0 || column == boxSide-1) {
                        printf("#");
                    }
                    
                    else if ((column == boxSide/2) && (row % 2 == 0)) {
                        printf("#");
                    }

                    else if ((row == boxSide/2) && (column % 2 == 0)) {
                        printf("#");
                    }                                     
                    
                    else {
                        printf(" ");
                    }

                column++;
                    
                }
   
                row++;
                printf("\n");
                
            }
 
    return 0;
}

推荐答案

停下来想一想：自己画框并看看它们是如何构建的。

Stop and think about it: draw the boxes yourself and look at how they are constructed.

#####    11111
#####    12221
## ##    12 21
#####    12221
#####    11111

是两个盒子

Is two boxes

#######    1111111
#######    1222221
#######    1233321
### ###    123 321
#######    1233321
#######    1222221
#######    1111111

三个盒子

到目前为止有道理吗？

所以你需要两个while循环：外部循环覆盖行，需要运行 2n + 1 次，其中 n 是框。 （因为你有2个一半要绘制，一个中间行。）

内部一个覆盖列，并且还运行 2n + 1 时间也是出于同样的原因。
在两个循环中，除非你在中心，否则打印＃。如果你在中心，打印。



如果你想的话很容易......但这是你的功课，所以我不编码for yoU！

Is three boxes
Make sense so far?
So you need two while loops: the outer one covers rows, and needs to run 2n + 1 times, where n is the number of boxes. (Because you have 2 "halves" to draw, and a single middle row.)
The inner one covers columns, and also runs 2n + 1 times for the same reason.
In side both loops, unless you are right at the centre, print "#". If you are at the centre, print " ".

Pretty easy if you think about it ... but this is your homework, so I'm not coding it for yoU!

使用光线投射。



您可以计算每个框的坐标和边界。 br />


然后你遍历每个单元格（每个col，逐行），看看它击中哪个框;如果原始的盒子计算是正确的，它只能击中一个而且只有一个。



（第一行单元格将全部击中外边界框;然后是最外面的2;下一个内盒顶部等等。）



颜色命中了带有该框字符的单元格。

Use "ray casting".

You can calculate the coordinates and "boundaries" of each box.

You then iterate over each "cell" (each col, by row) and see which box it "hits"; it can only hit one and only one if the original "box calculations" are correct.

(The first row of cells will all "hit" the outer bounding box; then the outer most 2; with the next inner box top hit, etc.)

"Color" hit cells with a character for that box.

考虑一下：

Consider this:

#######   3333333
#     #   3     3
# ### #   3 111 3
# # # #   3 1 1 3
# ### #   3 111 3
#     #   3     3
#######   3333333

你知道一个位置是否是一个盒子边框，取决于到盒子中心的距离。

You know if a position is a box border or not depending on the distance to center of boxes.

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