下划线克隆Mongoose对象和删除属性不起作用？ [英] Underscore's Cloning of Mongoose Objects and Deleting Properties Not Working?

问题描述

我正在使用Mongoose，我想在将JSON响应发送到客户端之前从我的Mongoose实例中删除 _id 属性。

I'm using Mongoose and I want to remove the _id property from my Mongoose instance before I send the JSON response to the client.

示例：

var ui = _.clone(userInvite);
delete ui["_id"];
console.log(JSON.stringify(ui)); //still has "_id" property, why?

之前没有用。

但是，如果我这样做：

var ui = JSON.parse(JSON.stringify(userInvite)); //poor man's clone
delete ui["_id"];
console.log(JSON.stringify(ui)); //"_id" is gone! it works!

我不明白为什么要调用删除在使用Underscore的克隆对象上不起作用，但如果我使用hacky JSON.string / JSON.parse，它可以工作。

I don't understand why calling delete on a cloned object using Underscore doesn't work, but if I do the hacky JSON.string/JSON.parse, it works.

有关此行为的任何想法吗？

Any thoughts on this behavior?

推荐答案

我刚遇到试图用 id 替换 _id 的类似问题。这样做对我有用：

I just came across a similar issue trying to replace _id with id. Doing this worked for me:

Schema.methods.toJSON = function(options) {
  var document = this.toObject(options);
  document.id = document._id.toHexString();
  delete(document._id);
  return document;
};

如果你替换 delete ui [_ id]，它可能会开始工作使用删除ui._id 或使用 toObject 而不是 _ .clone 。

Maybe it will start working if you replace delete ui["_id"] with delete ui._id or use toObject instead of _.clone.

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