如何将此代码的结果转换为小数？ [英] How do I convert the result of this code into a decimal?

问题描述

我正在尝试编写一个计算器，它将分数加在一起，所以我已经完成了，但不是给了我另一个分数而是给了我一个小数。



我尝试过：



公共类AddFractions扩展ConsoleProgram

{

public void run（）

{

double numeratorA = readInt（第一部分的分子是什么？）;

double denominatorA = readInt（第一部分的分母是什么？）;

double numeratorB = readInt（第二部分的分子是什么？）;

double denominatorB = readInt（第二部分的分母是什么？）;

double Sum = numeratorA / denominatorA * denominatorB / numeratorB;

系统.out.println（总和）;

}

}

解决方案

你应该单独计算结果的分子和denomiator：

n = n1 * d2 + n2 * d1

d = d1 * d2

然后（可选）找到他们的 GCD 以简化分数。

< blockquote class =quote>

引用：

我正在尝试编写一个计算器，它会将分数加在一起，所以我已经完成了它，但不是给了我另一个分数它给我一个小数代替。

你已经知道你不能将用户输入存储为 double 变量。你使用的是2个变量。

是什么让你认为你可以用计算结果来做？




I am trying to write a calculator where it adds fractions together, and so I have done it, but instead of giving me back another fraction it gives me a decimal instead.

What I have tried:

public class AddFractions extends ConsoleProgram
{
public void run()
{
double numeratorA = readInt("What is the numerator of the first fraction? ");
double denominatorA = readInt("What is the denominator of the first fraction? ");
double numeratorB = readInt("What is the numerator of the second fraction? ");
double denominatorB = readInt("What is the denominator of the second fraction? ");
double Sum = numeratorA/denominatorA * denominatorB/numeratorB;
System.out.println(Sum);
}
}

解决方案

You should separately compute the numerator and denomiator of the result:
n = n1*d2 + n2*d1
d = d1*d2
and then (optionally) find their GCD in order to simplify the fraction.




Quote:

I am trying to write a calculator where it adds fractions together, and so I have done it, but instead of giving me back another fraction it gives me a decimal instead.


You already have the knowledge that you can't store the user input as a fraction in a double variable. You are using 2 variables.
What make you think that you can do it with the result of a calculation ?




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