Mysql_fetch_array（）期望参数1是资源，布尔值在 [英] Mysql_fetch_array() expects parameter 1 to be resource, boolean given in

问题描述

if（isset（$ _ POST ['submit']））

{

session_start（）;

$ username = mysql_real_escape_string（ $ _POST ['username']）;

$ password = mysql_real_escape_string（$ _ POST ['password']）;

$ query = mysql_query（SELECT * FROM user where username = $ username和

密码= $密码）;

$ row = mysql_fetch_array（$ query）;

if（$ row [ 'username'] == $ username&& $ row ['password'] == $ password）

{

echowellcomo;

}否则{

echo输入正确的详细信息;

}

}



我尝试了什么：



任何人都可以为此解决这个问题

解决方案

_POST ['submit']））

{

session_start（）;

username = mysql_real_escape_string（

_POST ['username']）;

if(isset($_POST['submit']))
{
session_start();
$username = mysql_real_escape_string($_POST['username']);
$password = mysql_real_escape_string($_POST['password']);
$query = mysql_query("SELECT * FROM user where username=$username and
password=$password");
$row = mysql_fetch_array($query);
if($row['username']==$username && $row['password']==$password)
{
echo "wellcomo";
}else{
echo "enter correct details";
}
}

What I have tried:

can any one sugget me solution for this

解决方案

_POST['submit']))
{
session_start();

username = mysql_real_escape_string(

_POST['username']);

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