使用函数为PHP生成数字 [英] Using functions to generate numbers for PHP
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问题描述
我在练习中遇到问题
创建一个程序,随机生成-3到3之间的数字并显示数字。如果数字为零,1和-1,程序也应该继续
当数字不是-1,0或1时,程序将显示Good Job !否则,程序将显示无效
请让我理解这个编码!!
我尝试过:
Im having trouble with this exercise
Create a program that randomly generate numbers between -3 and 3 and display the number. The program should also continue if the numbers are zero, 1 and -1
When the numbers is not -1, 0 or 1, the program will display "Good Job!" otherwise, the program will display "invalid"
PLEASE MAKE ME UNDERSTAND THIS CODING!!
What I have tried:
echo "<h3> Activity 1: continue function </h3>";
$random = rand(-3,3){
Echo "The random number is: $random";
echo "<br>"
推荐答案
random = rand(-3,3){
Echo 随机数为:
random = rand(-3,3){ Echo "The random number is:
random;
echo < br>
[更新,感谢 Mohibur Rashid ]
你的意思是
[Updated, thanks to Mohibur Rashid]
Do you mean
while (true)
{
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