在React JS中按日期排序数组 [英] Sort array by dates in React JS
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问题描述
我有一个对象数组如下:
让cars = [
{id:20 ,里程:41300,制造:高尔夫,initialRegistration:09/02/2010},
{id:21,里程:51300,制造:帕萨特 ,initialRegistration:06/04/2012},
{id:22,里程:61300,make:Audi,initialRegistration:02/01/2018},
{id:23,里程:20300,make:Touran,initialRegistration:17/09/2013},
{id:24,里程:10300 ,make:Polo,initialRegistration:26/07/2014}
];
我想按 initialRegistration
排序。
我试着这样做:
let sortedCars = cars.sort((a,b)=> Date.parse(a.initialRegistration) - Date.parse(b.initialRegistration));
let sortedCars1 = cars.sort((a,b)=> new Date(a.initialRegistration) - new Date(b.initialRegistration));
let sortedCars2 = cars.sort((a,b)=> new Date(a.initialRegistration).getTime() - new Date(b.initialRegistration).getTime());
但这些尝试都没有奏效。我得到的结果是:
高尔夫 - 09/02/2010
帕萨特 - 06/04/2012
奥迪 - 02/01/2018
途安 - 17/09/2013
Polo - 26/07/2014
解决方案
使用 日期
构造函数并执行类似的操作。
let sortedCars1 = cars.sort((a,b)=> new Date(... a.initialRegistration.split('/')。reverse()) - new Date(... b。 。initialRegistration.split( '/')反向()));
让汽车= [{id:20,里程:41300,制造:高尔夫,initialRegistration:09/02/2010},{id:21,里程 :51300,make:Passat,initialRegistration:06/04/2012},{id:22,里程:61300,make:Audi,initialRegistration:02/01 / 2018},{id:23,里程:20300,make:Touran,initialRegistration:17/09/2013},{id:24,里程:10300, make:Polo,initialRegistration:26/07/2014}]; let sortedCars1 = cars.sort((a,b)=> new Date(... a.initialRegistration.split('/') .reverse()) - 新日期(... b.initialRegistration.split('/')。reverse())); console.log(sortedCars1);
或者使用 String#localeCompare
日期字符串。
let sortedCars1 = cars.sort((a,b)=>
a.initialRegistration.split('/')。reverse()。join()。localeCompare(b.initialRegistration.split('/')。reverse()。join()));;
让汽车= [{id:20,里程:41300,制造:高尔夫,initialRegistration:09/02/2010},{id:21,里程 :51300,make:Passat,initialRegistration:06/04/2012},{id:22,里程:61300,make:Audi,initialRegistration:02/01 / 2018},{id:23,里程:20300,make:Touran,initialRegistration:17/09/2013},{id:24,里程:10300, make:Polo,initialRegistration:26/07/2014}]; let sortedCars1 = cars.sort((a,b)=> a.initialRegistration.split('/')。reverse()。join ().localeCompare(b.initialRegistration.split( '/')反向()加入()。));执行console.log(sortedCars1);
I have an array of objects as follows :
let cars = [
{"id":20,"mileage":41300,"make":"Golf", initialRegistration:"09/02/2010"},
{"id":21,"mileage":51300,"make":"Passat", initialRegistration:"06/04/2012"},
{"id":22,"mileage":61300,"make":"Audi", initialRegistration:"02/01/2018"},
{"id":23,"mileage":20300,"make":"Touran", initialRegistration:"17/09/2013"},
{"id":24,"mileage":10300,"make":"Polo", initialRegistration:"26/07/2014"}
];
And I want to sort it by initialRegistration
.
I tried to do it as follows :
let sortedCars = cars.sort((a, b) => Date.parse(a.initialRegistration) - Date.parse(b.initialRegistration));
let sortedCars1 = cars.sort((a, b) => new Date(a.initialRegistration) - new Date(b.initialRegistration));
let sortedCars2 = cars.sort((a, b) => new Date(a.initialRegistration).getTime() - new Date(b.initialRegistration).getTime());
But none of these attempts did not work. The results that I get is :
Golf - 09/02/2010
Passat - 06/04/2012
Audi - 02/01/2018
Touran - 17/09/2013
Polo - 26/07/2014
解决方案
Use Date
constructor and do something like this.
let sortedCars1 = cars.sort((a, b) => new Date(...a.initialRegistration.split('/').reverse()) - new Date(...b.initialRegistration.split('/').reverse()));
let cars = [{
"id": 20,
"mileage": 41300,
"make": "Golf",
initialRegistration: "09/02/2010"
}, {
"id": 21,
"mileage": 51300,
"make": "Passat",
initialRegistration: "06/04/2012"
}, {
"id": 22,
"mileage": 61300,
"make": "Audi",
initialRegistration: "02/01/2018"
}, {
"id": 23,
"mileage": 20300,
"make": "Touran",
initialRegistration: "17/09/2013"
}, {
"id": 24,
"mileage": 10300,
"make": "Polo",
initialRegistration: "26/07/2014"
}];
let sortedCars1 = cars.sort((a, b) => new Date(...a.initialRegistration.split('/').reverse()) - new Date(...b.initialRegistration.split('/').reverse()));
console.log(sortedCars1);
Or by string comparison using String#localeCompare
after reversing the date string.
let sortedCars1 = cars.sort((a, b) =>
a.initialRegistration.split('/').reverse().join().localeCompare(b.initialRegistration.split('/').reverse().join()));
let cars = [{
"id": 20,
"mileage": 41300,
"make": "Golf",
initialRegistration: "09/02/2010"
}, {
"id": 21,
"mileage": 51300,
"make": "Passat",
initialRegistration: "06/04/2012"
}, {
"id": 22,
"mileage": 61300,
"make": "Audi",
initialRegistration: "02/01/2018"
}, {
"id": 23,
"mileage": 20300,
"make": "Touran",
initialRegistration: "17/09/2013"
}, {
"id": 24,
"mileage": 10300,
"make": "Polo",
initialRegistration: "26/07/2014"
}];
let sortedCars1 = cars.sort((a, b) =>
a.initialRegistration.split('/').reverse().join().localeCompare(b.initialRegistration.split('/').reverse().join()));
console.log(sortedCars1);
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