Webpack - 构建没有依赖关系的bundle [英] Webpack - build bundle without dependencies

问题描述

我想知道是否可以使用一些javascript文件构建一个包但没有依赖关系？

I;m wondering if it's possible to build a bundle with some javascript files but without dependencies?

我想要使用React组件的小包（每个反应组件）在我的例子中是由几个反应组件构建的，例如注释组件包含注释框，列表和表单），
我可以通过在webpack中指定几个入口点将React组件拆分为单独的文件，但是如果我有：
1.组件评论
2.组件通讯
并且它们都需要ReactDOM，将生成的文件将具有600kb，其中我的反应组件仅包含~100行js代码。

I want to have small bundles with React components (each react component in my case is builded from few react components, for example Comment component incldues comment box, list, and form), I can split React components to a separate files by specifying few entry points in webpack, but if I have: 1. Component comment 2. Component newsletter and both of them require ReactDOM, files which will be generated will have like 600kb, where my react components contain only ~100 lines of js code.

我想再增加一个文件，其中包含来自require（'react-dom'）的所有代码，而这两个文件只会有可能是React组件代码吗？

I would like to have one more file which will contain all the code which would come from "require('react-dom'), and those two files which will only have the React component code. is that possible?

我目前的设置：

'use strict';
import path from 'path';
import CommonsChunkPlugin from "webpack/lib/optimize/CommonsChunkPlugin";
module.exports = {
    entry: {
        app: "./app.js",
        newsletter: "./components/renderers/newsletter.renderer.js",
        comment: "./components/renderers/comment.renderer.js"
    },
    output: {
        path: path.join(__dirname),
        filename: "built/[name].entry.js"
    },
    devtool: 'sourcemaps',
    cache: true,
    debug: true,
    module: {
        loaders: [
            {
                test: /\.jsx?$/,
                exclude: [/(node_modules)/],
                loader: 'babel'
            }
        ],
        resolve: {
            extensions: ['', '.js', '.jsx']
        }
    },
    plugins: [
        new CommonsChunkPlugin({
            name: "comment.js",
            chunks: ["comment", "app"],
            minChunks: 2
        }),
        new CommonsChunkPlugin({
            name: "newsletter.js",
            chunks: ["newsletter", "app"],
            minChunks: 2
        })
    ]
};

Comment.renderer.js：

Comment.renderer.js:

import CommentBox from './../comment/commentBox';
ReactDOM.render(
    <CommentBox/>,
    document.getElementById("comment")
);

Newsletter.renderer.js：

Newsletter.renderer.js:

import Newsletter from './../newsletter/newsletter';
ReactDOM.render(
    <Newsletter/>,
    document.getElementById("newsletter")
);

app.js：

'use strict';
import React from 'react';
import ReactDOM from 'react-dom';
import client from './lib/client';

推荐答案

好的我已经设法如何做到：

Ok I've managed how to do that:

import path from 'path';
import CommonsChunkPlugin from "webpack/lib/optimize/CommonsChunkPlugin";
module.exports = {
    entry: {
        vendor: ["react","react-dom", "underscore"],
        comment: "./components/renderers/comment.renderer.js",
        newsletter: "./components/renderers/newsletter.renderer.js"
    },
    output: {
        path: path.join(__dirname),
        filename: "built/[name].bundle.js"
    },
    devtool: 'sourcemaps',
    cache: true,
    debug: true,
    module: {
        loaders: [
            {
                test: /\.jsx?$/,
                exclude: [/(node_modules)/],
                loader: 'babel'
            }
        ],
        resolve: {
            extensions: ['', '.js', '.jsx']
        }
    },
    plugins: [
        new CommonsChunkPlugin({
            name: "vendor",
            minChunks: Infinity
        })
    ]
};

此部分：

minChunks: Infinity

将确保包含在vendor中的代码不是包含在任何其他包中。由于这种方法，评论和简报将只包含我的React组件。

will ensure that code included in bundle "vendor" is not included in any other bundle. Thanks to this approach, comment and newsletter will contain only my React components.

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