TypeScript和RegExp [英] TypeScript and RegExp

问题描述

TypeScript说：

TypeScript says:

$ 1 属性不存在于类型' {的值{（pattern：string，flags？：string）：RegExp; new（pattern：string，flags？：string）：RegExp; } '

The property '$1' does not exist on value of type '{ (pattern: string, flags?: string): RegExp; new(pattern: string, flags?: string): RegExp; }'

通过查看 lib中的定义可以解释该类型。 d.ts 附带 TypeScript 0.8.2 ：

interface RegExp {
    /** 
      * Executes a search on a string using a regular expression pattern, and returns an array containing the results of that search.
      * @param string The String object or string literal on which to perform the search.
      */
    exec(string: string): RegExpExecArray;
    /** 
      * Returns a Boolean value that indicates whether or not a pattern exists in a searched string.
      * @param string String on which to perform the search.
      */
    test(string: string): bool;
    /** Returns a copy of the text of the regular expression pattern. Read-only. The rgExp argument is a Regular expression object. It can be a variable name or a literal. */
    source: string;
    /** Returns a Boolean value indicating the state of the global flag (g) used with a regular expression. Default is false. Read-only. */
    global: bool;
    /** Returns a Boolean value indicating the state of the ignoreCase flag (i) used with a regular expression. Default is false. Read-only. */
    ignoreCase: bool;
    /** Returns a Boolean value indicating the state of the multiline flag (m) used with a regular expression. Default is false. Read-only. */
    multiline: bool;

    lastIndex: number;
}
declare var RegExp: {
    new (pattern: string, flags?: string): RegExp;
    (pattern: string, flags?: string): RegExp;
}

我的问题是如何更改/更新此内容以允许我参考 RegExp。$ 1 ， RegExp。$ 2 等？最好我可以单独声明，因为我不打算直接编辑 lib.d.ts （很可能会在更新后更换）

My question is how can I change/update this to allow me to reference RegExp.$1, RegExp.$2, etc.? Preferably something I can declare separately since I do not intend to directly edit lib.d.ts (which will most likely get replaced as it is updated)

我试过这个无济于事：

declare var RegExp: {
    new (pattern: string, flags?: string): RegExp;
    (pattern: string, flags?: string): RegExp;
    $1: any;
    $2: any;
    $3: any;
    $4: any;
    $5: any;
    $6: any;
    $7: any;
    $8: any;
    $9: any;    
}

我猜他们应该用类型 string <来声明/ code>实际上。但无论如何它都不会删除错误。

I guess they should be declared with type string actually. But in any case it doesn't remove the errors.

除此之外我还很好奇这究竟是什么意思（为什么声明有没有新？）：

In addition to this I'm also curious about what this means exactly (why is it declared with and without a new?):

new (pattern: string, flags?: string): RegExp;
(pattern: string, flags?: string): RegExp;

推荐答案

您的声明var 已经关闭。接口是开放的，所以你可以写：

Your declare var is close. Interfaces are open, so you can just write:

interface RegExp {
    $1: string;
    $2: string;
    // etc
}

关于第二个，这是因为新的RegExp（'[AZ]'）和 RegExp（'[AZ]'）都可以创建一个RegExp（在类型术语，它既是一个可调用函数又是一个构造函数。）

Regarding the second one, it's because new RegExp('[A-Z]') and RegExp('[A-Z]') both work to create a RegExp (in type terms, it's both an invokable function and a constructor function).

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