我想从一个文件中读取一个（例子）类似'@ 123 @ 123 @ 123'的模式。遇到@后，123将被存储在一个数组中，依此类推。 [英] I want to read a (example) pattern something like '@123@123@123' from a file. After encountering @, 123 to be stored in an array, and so on.

问题描述

我要阅读的实际文件如下：

@

1

2

。

。

90

@

1

2

。

。

90

@

1

。

。

$

@

我想读取文件，遇到@时，@之后的数据（这里是整数）必须读入数组。然后在数据传输到数组后，继续读取文件，当再次遇到@时，重复该过程并再次将@中的下一组数据存储在数组中。



我尝试了什么：



我试过这段代码，这给了我一个错误。我不明白这是什么错误。请帮我。显示错误的代码行如下：

My actual file to be read is something like:
@
1
2
.
.
90
@
1
2
.
.
90
@
1
.
.
90
@
I want to read the file, when @ is encountered, the data (here integers) after @ must be read into an array. Then after data is transferred to the array, resume reading the file, when @ is encountered again, repeat the process and store the next set of data after @ in the array again.

What I have tried:

I have tried this code,which is giving me an error. I don't understand what is the mistake. Please help me. The line of code that shows an error is below:

public void P()
        {
            while(s.hasNext())
            {
            String lineOfText = s.nextLine();
            if (lineOfText.startsWith("@"))
            
                
            {
            
            }
            
			codes[m] = s.nextInt();
			m++;
            
            }
		
        }

当我只有

@

1

2

。

。



在文件中，代码工作正常。但我的文件是像上面描述的iv'e模式。请帮忙。

When I have only
@
1
2
.
.
90
in the file, the code works fine. But my file is a pattern like iv'e described above. Please help.

推荐答案

试试这个：

Try this:

while(s.hasNext()) {
    String lineOfText = s.nextLine();
    if (lineOfText.startsWith("@")) {
        // ignore lines starting with @
    }
    else {
        codes[m] = Integer.parseInt(lineOfText);
        System.out.println("num: " + codes[m]);
        m++;
    }
}

查看你的代码。

如果你读的行开头会怎么样'@'？如果它做了什么呢？如果不是，会发生什么？在实践中是否做了什么？



并帮自己一个忙：用文本编辑器仔细查看输入文件（可能是二进制查看器好）：你在这里描述了同一个问题中两种截然不同的格式，数据不能同时存在！

Look at your code.
What happens if the line you read starts with '@'? What does it do if it does? What happens if it isn't? Does the if do anything in practice?

And do yourself a favour: have a good close look at your input file with a text editor (and possible a binary viewer as well): you describe two very different formats in the same question here, and the data cannot be both!

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