如何使用var作为单例的频率？ [英] How to use a var as a frequency with simpletones?

问题描述

我希望能够输入用户输入的号码：

  <  输入    type     =  number    id     =  投注    min     =  0    max     =   42   值    =  6 >  

并将其用作playTone的频率（ ）使用simpleTones.js：

  var  bets =  document  .getElementById（  bets）; 
 playTone（bets.value，  sine， 6 ）

我尝试过：



我已经尝试过使用一些simpleTones代码来看看我是否可以改变它的行为方式但是作为一个js初学者我不是很确定要开始。作为参考，这里是我认为可能相关的源代码片段：

 playTone =（频率，类型，持续时间）= > {
  if （type ===  undefined ）{
 type =  正弦; 
} 
  if （duration ===  undefined ）{
 duration =  1 。 3 ; 
} 
  if （频率===  undefined ）{
 frequency =  440 ; 
} 

解决方案

使用parseInt计算出来！

 function playBets（）{
 
 var bets = document.getElementById（bets）; 
 bets = parseInt（bets.value）+ 440; 
 
 playTone（440，sine，6）
 playTone（parseInt（bets），sine，6）
 
} 

I would like to be able to take a user inputted number:

<input type = "number" id = "bets" min = "0" max = "42" value = "6">

And use that as the frequency for playTone() using simpleTones.js:

var bets = document.getElementById("bets"); 
playTone(bets.value, "sine", 6)

What I have tried:

I've tried playing around with some of the simpleTones code to see if I can change the way it behaves but as a js beginner I'm not really sure to start. For reference, here is a snippet of the source I thought might be relevant:

playTone = (frequency, type, duration) => {
	if (type === undefined) {
		type = "sine";
	}
	if (duration === undefined) {
		duration = 1.3;
	}
	if (frequency === undefined) {
		frequency = 440;
	}

解决方案

Figured it out using parseInt!

function playBets() { 

		var bets = document.getElementById("bets"); 
		bets = parseInt(bets.value) + 440; 

		playTone(440, "sine", 6)
		playTone(parseInt(bets), "sine", 6)

	}

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