你怎么摆脱这两个恼人的错误plzzzz [英] How do you get rid of these two annoying errors plzzzz

问题描述

我正在尝试编辑页面，编辑后啊应该能够更新信息，换句话说我正在做编辑页面和更新，但我可以让编辑页面编辑或更新信息。更新页面中的




，我收到这些错误并一直试图解决它。



这是错误号1.

未定义变量：userName 在 C：\ wamp64 \过网络中的内容 30  

这是错误号码。 2

：未定义的变量：密码在 C：\ wamp64 \ www。\\\\\\\\\\\\\\\\ php \update.php在线 30  

，这就是我到目前为止所做的，我真的需要从中移动一个，但我必须得到工作而且我被卡住了，有人可以帮助我在这里。非常感谢



我尝试过：



这是更新码。

 <   pre  >  <？ php 
 
 session_start（） ; 
 $ _SESSION ['  user']; 
  //   $ title = $ _ POST ['title'];  
 $ firstname = $ _ POST ['  firstname']; 
 $ lastname = $ _ POST ['  lastname']; 
  //   $ address = $ _ POST ['address'];  
 < span class =code-comment> //   $ txtemail = $ _ POST ['txtemail'];  
  //   $ gender = $ _ POST ['gender'];  
  / /    
 
 
  //  创建与数据库的连接 
 $ db_host = '  localhost'< /跨度>; 
 $ db_username = '  root'; 
 $ db_password =  ; 
 
 
  //  检查连接 
  $ con  = mysqli_connect（$ db_host，$ db_username，$ db_password）或 die（mysqli_connect_error（））; 
 
  //  选择数据库 
 mysqli_select_db（$ con， '  food'）或 die（mysqli_error） （$ CON））; 
 
 
  //   $ userName = $ _ SESSION ['user'];  
  //   $ password = $ _ SESSION ['user'];  
 
 $ sql =   SELECT * FROM member WHERE userName ='$ userName'AND pword = md5（ '$口令'）; 
 $ result = mysqli_query（$ con，$ sql）或 die（ 错误： .mysqli_error（））; 
 
  //  从数据库收集信息 
 if（$ result ）
 {
 $ rowcount = mysqli_num_rows（$ result）; 
 
 if（$ rowcount == 1）
 {
 
  //  使用编辑表单中的信息更新数据库 
 $ update =  更新成员SET firstname ='$ firstname'WHERERE userName ='。$ _ SESSION ['  user']。 '; 
 $ update =   UPDATE成员SET lastname ='$ lastname'WHERE userName =' 。$ _ SESSION ['  user']。 '; 
 
  //   mysqli_query（$ con，$ update）或die（mysqli_error（$ con）） ）;  
 
 if（mysqli_query（$ con，$ update））
 {
 
  echo   < script type = \text / javascript \> 
 alert（ '配置文件已成功更新。'）; 
 window.location = \profile.php \; 
< / script>; 
 
 mysqli_close（$ con）; 
 header（  location：edit.php）; 
 
} 
  else  
 {
  echo   < scrip type = \text / javascript \> 
 alert（'密码错误'）; 
 window.locaton = \edit.php \; 
< / script>; 
} 
} 
 
} 
 
 
 
 
 ？ >  

解决方案

_SESSION [' 用户];
//

title =

_POST [ '标题'];

I am trying to do an edit page and after editing ah should be able to update the information in other words am doing both an edit page and update but i can get the edit page to either edit or update the information.


in the update page, I am get these errors and have been banging my head trying to solve it.

this is the error no 1.

Undefined variable: userName in C:\wamp64\www\luana_itec244\php\update.php on line 30

this is error no. 2

: Undefined variable: password in C:\wamp64\www\luana_itec244\php\update.php on line 30

and here is what i have so far, I really need to move one from this but I have to get the working and I am stuck, can someone please help me out here. much thanks

What I have tried:

this is the update codes.

<pre><?php
		
			session_start();
			$_SESSION['user'];
			//$title=$_POST['title'];
			$firstname=$_POST['firstname'];
			$lastname=$_POST['lastname'];
			//$address=$_POST['address'];
			//$txtemail=$_POST['txtemail'];
			//$gender=$_POST['gender'];
			//
			
			
			//create connection to database
			$db_host='localhost';
			$db_username='root';
			$db_password="";
			
			
				//check connection
				$con = mysqli_connect($db_host, $db_username, $db_password) or die(mysqli_connect_error());
			
				//select the database
				mysqli_select_db($con, 'food') or die(mysqli_error($con));
				
				  	
					//$userName=$_SESSION['user'];
					//$password=$_SESSION['user'];
				 
					$sql="SELECT * FROM member WHERE userName='$userName' AND pword=md5('$password')";
					$result=mysqli_query($con, $sql) or die ("Error:" .mysqli_error());
					
					//collect info from database
					if($result)
					{
						$rowcount=mysqli_num_rows($result);
						
						if($rowcount==1)
						{
							
							//update database with information from the edit form
							$update="UPDATE member SET firstname='$firstname' WHERE userName='".$_SESSION['user']."'";
							$update="UPDATE member SET lastname='$lastname' WHERE userName='".$_SESSION['user']."'";
							
							//mysqli_query($con, $update) or die(mysqli_error($con));
							
							if(mysqli_query($con, $update))
							{                               
						
								echo "<script type=\"text/javascript\">
									alert('Profile successfully updated.');
									window.location=\"profile.php\";
									</script>";
									
								mysqli_close($con);
								header("location:edit.php");
								
							}
							else
							{
								echo "<scrip type=\"text/javascript\">
										  alert('Incorrect password');
										  window.locaton=\"edit.php\";
									  </script>";
							}
						}	
						
					}
			
		
		

?>

解决方案

_SESSION['user']; //

title=

_POST['title'];

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