JSON.parse使用reviver函数 [英] JSON.parse using reviver function

问题描述

如何使用JSON.parse reviver方法编辑某个值。
我只想编辑声明为lastname的每个键，然后返回新值。

How to use JSON.parse reviver method to edit a certain value. I just want to edit every key which is declared as lastname and than return the new value.

var myObj = new Object();
myObj.firstname = "mike";
myObj.lastname = "smith";

var jsonString = JSON.stringify(myObj);
var jsonObj = JSON.parse(jsonString, dataReviver);

function dataReviver(key, value)
{
    if(key == 'lastname')
    {
        var newLastname = "test";
        return newLastname;
    }
}

推荐答案

之后检查特殊情况，您只需要默认传回未修改的值：

After checking for the special case(s), you simply need to pass back unmodified values by default:

var myObj = new Object();
myObj.firstname = "mike";
myObj.lastname = "smith";

var jsonString = JSON.stringify(myObj);
var jsonObj = JSON.parse(jsonString, dataReviver);

function dataReviver(key, value)
{ 
    if(key == 'lastname')
    {
        var newLastname = "test";
        return newLastname;
    }

  return value;  // < here is where un-modified key/value pass though

}

JSON.stringify(jsonObj )// "{"firstname":"mike","lastname":"test"}" 

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