我如何在java中执行此代码 [英] How do I do this code in java

问题描述

我需要创建一个随机生成100万个不同车辆登记牌的代码。

盘子需要：

- 包含3个数字

- 由3个字母组成，不包括元音

- 字母和数字需要用破折号分隔

- 随机生成的国家代码需要添加到盘子的末尾，它需要是以下之一（CA，ZN， MP，EC，L，GP，NC，FS，NW）

- 所有内容都需要在GUI中显示，当您按下生成按钮时，它会生成所有内容



我尝试了什么：



我试过创建数组和for循环而我的代码不能正常工作

I need to create a code which randomly generates 1 million different vehicle registration plates.
The plates need:
- to consist of 3 numbers
- to consist of 3 letters excluding vowels
-the letters and numbers need to be separated by a dash
- a randomly generated country code needs to be added to the end of the plate, it needs to be one of the following ( CA, ZN, MP, EC, L, GP, NC, FS, NW)
- everything needs to be displayed in a GUI and when you press the generate button it generates everything

What I have tried:

I have tried creating arrays and for loops and my code is not working

推荐答案

跟踪：使用JFC创建GUI Swing（The Java™Tutorials） [ ^ ]，随机（Java平台）表格SE 8） [ ^ ]。



尽管在GUI上一次显示一百万个项目会让你的用户感到烦恼。

Trail: Creating a GUI With JFC/Swing (The Java™ Tutorials)[^], Random (Java Platform SE 8 )[^].

Although, showing a million items on the GUI in one go will really annoy your users.

假设有五个元音（即考虑' Y '一个辅音），你可以有

Assuming five vowels (that is considering 'Y' a consonant), you could have

10 ^ 3 * 21 ^ 3 * 9 = 83349000

不同的盘子。



所以你可以在<$中选择一个随机数c $ c> [0..83348999] 范围并使用它生成板块字符串。我将向您展示代码：

different plates.

So you can choose a random number in the [0..83348999] range and generate the plate string using it. I am going to show you the code:

import java.util.Random;

class Plate
{
  static final int PLATES = 83349000;
  static String plate(int n)
  {
    char [] dgt = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' };
    char [] letter = { 'B', 'C', 'D', 'F', 'G', 'H', 'J', 'K', 'L', 'M', 'N', 'P', 'Q', 'R', 'S', 'T', 'V', 'W', 'X', 'Y', 'Z' };
    String [] cc = { "CA", "ZN", "MP", "EC", "L", "GP", "NC", "FS", "NW" };

    String p = "";

    if ( n<0 || n >= PLATES) return p;
    int rem;
    for ( int i = 0; i<3; i++)
    {
      rem = n % 10;
      p += dgt[rem];
      n = (n - rem) / 10;
    }
    p += "-";

    for ( int i = 0; i<3; i++)
    {
      rem = n % 21;
      p += letter[rem];
      n = (n - rem) / 21;
    }
    p += "-";
    rem = n % 9;
    p += cc[rem];
    return p;
  }

  public static void main(String arg[])
  {
    int n;
    Random rand = new Random();
    // generate and show 10 random plates (repetition is allowed)
    for (n=0; n<10; ++n)
    {
      int r = rand.nextInt(PLATES);
      System.out.printf( "%3d %s\n", (n+1), plate( r) );
    }

  }
}

现在你必须生成1000000个这样的板块（我假设）避免重复。

你可以使用（如果你的编程盒有足够的内存）这里显示的算法：从甲板上随机抽取5张卡片[ ^ ]来制作技巧。



最后你必须创建一个 GUI ，可能正在使用，如Swing Framework所示。这个艺术步骤非常适合您。

Now you have to generate 1000000 of such plates (and I assume) avoiding repetitions.
You could use (if your programming box has enough memory) the algorithm shown here: Random extraction of 5 cards from a deck[^] to make the trick.

Finally you have to create a GUI for it, possibly using, as suggested the Swing Framework. This artistic step is very up to you.

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