列表框中显示的Treeview节点 [英] Treeview nodes shown in listbox

问题描述

单击按钮时（MoveBtn）如何将树视图中选定的项目复制到列表框。

When a button is clicked (MoveBtn )How do I copy over the items selected in my tree view to a listbox.

private void MoveBtn_Click(object sender, EventArgs e)
{

    Listbox1.Items.Clear();
    foreach (var node in treeView1.Nodes)
    {
        Listbox1.Items.Add(node);
    }
    Listbox1.Show();

}



此代码仅显示根，但不显示子节点选择。但是我也希望显示子节点 - 如果可能的话只显示子节点



我尝试了什么：

}

This code only shows the root, but not the child nodes which are selected. But I want to show the child nodes too -- if possible only the child nodes

What I have tried:

Listbox1.Items.Clear();
foreach (var node in treeView1.Nodes)
{
    Listbox1.Items.Add(node);
}
Listbox1.Show();

推荐答案

为了复制所有节点，您需要递归。考虑下面的例子（抱歉打字错误，我手边没有编译器）

In order to copy all the nodes you need a recursion. Consider the following example (sorry about the typos, I don't have a compiler at hand at the moment)

public void Method1() {
   Listbox1.Items.Clear();
   AddNodes(treeView1.SelectedNode, Listbox1);
}

public void AddNodes(TreeNode parentNode, ListBox lb) {
   foreach (var node in parentNode.Nodes) {
      lb.Items.Add(node);
      AddNodes(node, lb);
   }
}

注意：Web Ms TreeView提供了对所有已检查TreeNode的轻松访问：WinForms TreeView TreeView不能。 br />


因此，您需要一种方法来获取所有TreeNodes，然后您需要选择所有TreeNodes被检查。此示例使用Eric Lippert提倡的经典基于堆栈的方法，以避免可能的递归堆栈溢出：

Note: the Web Ms TreeView offers easy access to all checked TreeNodes: the WinForms TreeView TreeView does not.

So, you need a method to get all the TreeNodes, and then you need to select all the TreeNodes that are checked. This example uses the "classic" stack-based method that Eric Lippert advocates in order to avoid possible stack overflow with recursion:

public IEnumerable<TreeNode> GetNodes(TreeNodeCollection nodes)
{
    var stack = new Stack<TreeNode>();

    foreach (TreeNode node in nodes)
    {
       stack.Push(node);
    }

    while (stack.Count > 0)
    {
        var current = stack.Pop();
        yield return current;

        foreach (TreeNode child in current.Nodes)
        {
            stack.Push(child);
        }
    }
}

然后过滤它们以找到选中的节点：

Then filter them to find the checked Nodes:

listBox1.Items.Clear();

var checkedNodes = GetNodes(treeView1.Nodes)
    .Where(nd => nd.Checked)
    .OrderBy(nd => nd.Text)  // remove if you don't want sorted 
    .ToArray();

listBox1.Items.AddRange(checkedNodes.ToArray());

这篇关于列表框中显示的Treeview节点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！