如何将此lambda函数转换为def格式？ [英] How do I transform this lambda function into def format?

问题描述

我试图理解这段代码的细节：

I am trying to understand the details of this code do:

 prune = lambda tree : [prune(branch) for branch in tree if branch != []]

l = [[[[], []], [[], []]], [[], [], []]]
prune(l)

但是我还没有学过lambda函数。



我尝试过：



我试图将其分解为def函数格式

But i have not yet learnt the lambda function.

What I have tried:

I am trying to break it down to the def function format

def prune(tree):
    for branch in tree:
        if branch!=[]:
             prune(branch)
    return branch
print prune([[[[], []], [[], []]], [[], [], []]])

但它没有给出相同的结果，我做错了什么？

But it doesn't give the same result, what am I doing wrong?

推荐答案

def prune(tree):
    result = []
    for branch in tree:
        if branch != []:
            result.append(prune(branch))
    return result

你几乎就在那里;你错过的唯一一步是将元素添加到结果列表中。

You were almost there; the only step you missed, was adding the elements to a result list.

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