我该怎么做才能解决此错误 [英] What can I do get this error fix

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问题描述

hi


我有这个错误,我真的不知道如何解决它。



这是错误



解析错误:语法错误,意外'  mysqli_error'(T_STRING)  C:\ wamp64 \过网站上的#luana_itec244 \\\ [@ b 

这是错误的来源



我尝试过:



 <   pre  >  <? php 


if(isset( $ _POST [' submit']))
{
// 从表单中捕获变量并存储在php变量中

$ title = $ _ POST [' title'];
$ firstname = $ _ POST [' firstname'];
$ lastname = $ _ POST [' lastname'];
$ address = $ _ POST [' address'];
$ txtemail = $ _ POST [' txtemail'];
$ gender = $ _ POST [' gender'];
$ userName = $ _ POST [' userName'];
$ pword = $ _ POST [' pword'];

// 连接服务器

$ db_host = localhost;
$ db_username = root;
$ db_password = ;
$ con = mysqli_connect($ db_host,$ db_username,$ db_password) die(mysqli_connect_error) ());

// 选择要查询的数据库

mysqli_select_db($ con,' food' die(mysqli_error($ con));
$ sql = SELECT * FROM member WHERE userName ='$ userName';
$ result = mysqli_query($ con,$ sql) die( 错误: mysqli_error());
$ rowcount = mysqli_num_rows($ result);

if($ rowcount> = 1)
{
echo < script type = \text / javascript \;
alert('用户名已存在');
窗口。 location = \register.html \;
< / script>
;
}
其他
{
// < span class =code-comment>将数据插入表中

$ sql = INSERT INTO成员
VALUES('$ title','$ firstname','$ lastname','$ address','$ txtemail' ,'$ gender','$ userName',MD5('$ pword'))
;

if(mysqli_query($ con,$ sql))
{
mysqli_close($ con);
header( location:welcome.php);

}
else
{
echo 插入数据库时​​出错 .mysqli_error($ con);
}



}



}
?>

解决方案

_POST [' submit']))
{
// 从表单中捕获变量并存储在php变量中


title =


_POST [' title'];


hi
i have this error and I really dont know how to go about fix it.

this is the error

Parse error: syntax error, unexpected 'mysqli_error' (T_STRING) in C:\wamp64\www\luana_itec244\php\register.php on line 2



this is where the error is coming from

What I have tried:

<pre><?php
		
		
		if(isset($_POST['submit']))
		{
			//capture the variable from the form and store in php variables
			
			$title=$_POST['title'];
			$firstname=$_POST['firstname'];
			$lastname=$_POST['lastname'];
			$address=$_POST['address'];
			$txtemail=$_POST['txtemail'];
			$gender=$_POST['gender'];
			$userName=$_POST['userName'];
			$pword=$_POST['pword'];
			
			//connecting to the server
			
			$db_host="localhost";
			$db_username="root";
			$db_password="";
			$con = mysqli_connect($db_host,$db_username,$db_password) or die (mysqli_connect_error());
			
			//select the database you want to query
			
			mysqli_select_db($con, 'food') or die (mysqli_error($con));
			$sql = "SELECT * FROM member WHERE userName = '$userName'";
			$result=mysqli_query($con,$sql) or die("error:" mysqli_error());
			$rowcount=mysqli_num_rows($result);
			
			if($rowcount >= 1)
			{
				echo "<script type=\"text/javascript\";
				alert('username already exist');
				window.location=\"register.html\";
				</script>";
			}
			else
			{
				//insert data into table
				
				$sql = "INSERT INTO member 
				VALUES('$title', '$firstname', '$lastname', '$address', '$txtemail', '$gender', '$userName', MD5('$pword'))";
				
				if(mysqli_query($con, $sql))
					{
						mysqli_close($con);
						header("location:welcome.php");
						
					}
					else
					{
						echo "Error inserting into database".mysqli_error($con);
					}
			
				
				
			}
			
			
			
		}
?>

解决方案

_POST['submit'])) { //capture the variable from the form and store in php variables


title=


_POST['title'];


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