Chrome检查器控制台无法与版本54.0.2840.99一起使用 [英] Chrome inspector console does not work with version 54.0.2840.99

问题描述

我使用node-inspector来调试JS版本54.0.2840.99的JS。
我在一个windows cmd控制台中输入node-inspector并在节点--debug-brk l：\dev \另一个Windows cmd控制台中的debug\test.js。在Chrome中打开http://127.0.0.1:8080/?ws=127.0.0.1:8080&port=5858。它可以照常调试。但我在Chrome控制台输入1 + 2，按Enter，没有任何反应。我希望3输出到Chrome控制台。它适用于Chrome版本48.0.2564.116。我没有使用其他Chrome版本进行测试。

I use node-inspector to debug JS with Chrome version 54.0.2840.99. I enter "node-inspector" in one windows cmd console and "node --debug-brk l:\dev\debug\test.js" in another windows cmd console. Open "http://127.0.0.1:8080/?ws=127.0.0.1:8080&port=5858" in Chrome. It's able to debug as usual. But I input "1 + 2" in Chrome console, press "Enter", nothing happen. I would expect "3" is output to Chrome console. It did work with Chrome version 48.0.2564.116. I did not test with other Chrome versions.

这是新Chrome版本的缺陷吗？如何解决问题？
我拍摄的图片如下：

Is it a defect of the new Chrome versions? How to resolve the problem? I captured the pictures as below:

推荐答案

这是由Chrome弃用造成的 KeyboardEvent.keyIdentifier 。

It's caused by Chrome deprecating KeyboardEvent.keyIdentifier.

解决方法是将 keyIdentifier 添加回 KeyboardEvent 原型。

The workaround would be to add keyIdentifier back to the KeyboardEvent prototype.

我还注意到 KeyboardEvent.key 字符串值是不同的从 KeyboardEvent.keyIdentifier 租用，所以我在下面显示如何处理这些差异。

I also noticed that the KeyboardEvent.key string values are different from those from KeyboardEvent.keyIdentifier so I show below how to handle those differences if needed.

Object.defineProperty(KeyboardEvent.prototype, 'keyIdentifier', {
    get: function() {
        switch (this.key) {
            case "ArrowDown":
                return "Down";
                break;
            case "ArrowLeft":
                return "Left";
                break;
            case "ArrowRight":
                return "Right";
                break;
            case "ArrowUp":
                return "Up";
                break;
            case "Tab":
                return "U+0009";
                break;
            case "Escape":
                return "U+001B";
                break;
            default:
                return this.key;
        } 
    }
});

简单地替换 isEnterKey（）是不够的以上代码处理此修复。

Simply replacing isEnterKey() is not sufficient and the above code handles this fix.

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