C中的分段错误,混淆了什么是错误的 [英] Segmentation fault in C, confused whats going wrong
问题描述
虽然提交了代码其结束分段错误,但表示堆栈溢出
我尝试过:
While submitted the code its ending up segmentation error , of saying stack overflow
What I have tried:
#include<stdio.h>
int main()
{
int twen=0,nine=0,other=0,n;
char cd[1000];
scanf("%d",n);
while(n--)
{
gets(cd);
if(cd[0] == 'G')
{
for(int i=0;cd[i]!='\0';i++)
{
if((cd[i]=='1') && (cd[i+1] == '9'))
{
nine+=2;
}
else if((cd[i]=='2') && (cd[i+1] == '0'))
{
twen+=2;
}
else if((cd[i]>2) && (cd[i+1]<9))
{
other+=2;
}
}
}
if(cd[0] == 'M')
{
for(int i=0;cd[i]!='\0';i++)
{
if((cd[i]=='1') && (cd[i+1] == '9'))
{
nine+=1;
}
else if((cd[i]=='2') && (cd[i+1] == '0'))
{
twen+=1;
}
else if((cd[i]>'2') && (cd[i+1]<'9'))
{
other+=1;
}
}
}
}
if(nine>twen)
printf("Date\n");
else if(other > twen || other > nine)
printf("No Date\n");
else
printf("No Date\n");
return 0;
}
推荐答案
我们无法告诉您 - 我们无法访问您的数据,因此我们可以'在完全相同的条件下尝试你的代码 - 这几乎肯定会与数据相关。
但这是你的第一个loop:
We can't tell you - we don't have access to your data, so we can't try your code under exactly the same conditions you can - and this is almost certainly going to be data related.
But this in your firstfor
loop:
else if((cd[i]>2) && (cd[i+1]<9))
应该看看在你的第二个像这样:
Should probably look like this in your second:
else if((cd[i]>'2') && (cd[i+1]<'9'))
虽然这不会解决你的问题!
但是,你的阵列已经结束了 cd
。
所以,这取决于你。
幸运的是,你有一个工具可以帮助你找出发生了什么:调试器。你如何使用它取决于你的编译器系统,但是一个快速的谷歌用于你的IDE名称和调试器应该给你你需要的信息。
放一个断点在函数的第一行,并通过调试器运行代码。然后查看您的代码,并查看您的数据并找出手动应该发生的事情。然后单步执行每一行检查您预期发生的情况正是如此。如果不是,那就是当你遇到问题时,你可以回溯(或者再次运行并仔细观察)以找出原因。
对不起,但我们不能为你做到这一点 - 时间让你学习一门新的(非常非常有用的)技能:调试!
That won't fix your problem though!
Probably though, you are running off the end of your array cd
.
So, it's going to be up to you.
Fortunately, you have a tool available to you which will help you find out what is going on: the debugger. How you use it depends on your compiler system, but a quick Google for the name of your IDE and "debugger" should give you the info you need.
Put a breakpoint on the first line in the function, and run your code through the debugger. Then look at your code, and at your data and work out what should happen manually. Then single step each line checking that what you expected to happen is exactly what did. When it isn't, that's when you have a problem, and you can back-track (or run it again and look more closely) to find out why.
Sorry, but we can't do that for you - time for you to learn a new (and very, very useful) skill: debugging!
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