从Android的Post方法不起作用 [英] Post method from android doesn't work
本文介绍了从Android的Post方法不起作用的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
所以，我试图让一个登录活动。它采用的数据库从MySQL所以我做了一个PHP Web服务1login.php。然后，我有方法makeHtt prequest（URL，方法，PARAMS）和LoginActivity类JSONParser类。但是有一个问题。我不能发送PARAMS到web服务，但是当我试图用GET方法，它的工作（有一些问题与符'@'）。我想了解如何使用POST方法。下面是C $ CS的$：
PHP（它工作得很好，所以我不认为这个问题是在这里）
＆LT; PHP
包括0conn.php;
$电子邮件= $ _ POST [电子邮件];
$ heslo = $ _ POST [heslo];
$传球= SHA1（$ heslo）;
$查询= mysqli_query（$康恩，选择jmeno，电子邮件，用户WHERE电子邮件=$电子邮件和heslo ='$通行证'）;
$水库=阵列（）;
$响应=阵列（）;
如果（mysqli_num_rows（$查询）== 1）{
$结果= mysqli_fetch_array（$查询）;
$水库[vysledek] = 1;
$水库[电子邮件] = $结果[电子邮件];
$水库[jmeno] = $结果[jmeno];
}
否则$水库[vysledek] = 0;
$响应[] = $资源;
mysqli_free_result（$查询）;
回声json_en code（$响应）;
？＆GT;
在JSONParser类：
包com.thevnkid93.ucebnice;
进口java.io.BufferedReader中;
进口java.io.IOException异常;
进口的java.io.InputStream;
进口java.io.InputStreamReader中;
进口java.io.UnsupportedEncodingException;
进口的java.util.List;
进口org.apache.http.HttpEntity;
进口org.apache.http.Htt presponse;
进口org.apache.http.NameValuePair;
进口org.apache.http.client.ClientProtocolException;
进口org.apache.http.client.HttpClient;
进口org.apache.http.client.entity.UrlEn codedFormEntity;
进口org.apache.http.client.methods.HttpGet;
进口org.apache.http.client.methods.HttpPost;
进口org.apache.http.client.utils.URLEn codedUtils;
进口org.apache.http.impl.client.DefaultHttpClient;
进口org.json.JSONArray;
进口org.json.JSONException;
进口org.json.JSONObject;
进口android.R.integer;
进口android.os.AsyncTask;
进口android.util.Log;
公共类JSONParser {
静态的InputStream是= NULL;
静态的JSONObject jObj = NULL;
静态JSONArray jArr = NULL;
静态JSON字符串=;
//功能得到URL JSON
//通过HTTP POST或GET方法
公共静态JSONArray makeHtt prequest（URL字符串，字符串的方法，
名单＆LT;的NameValuePair＆GT; PARAMS）{
//使HTTP请求
尝试 {
//检查请求的方法
如果（method.equals（POST））{
//请求方法是POST
// defaultHttpClient
DefaultHttpClient的HttpClient =新DefaultHttpClient（）;
HttpPost httpPost =新HttpPost（URL）;
httpPost.setEntity（新UrlEn codedFormEntity（PARAMS，UTF-8））;
HTT presponse HTT presponse = httpClient.execute（httpPost）;
HttpEntity httpEntity = HTT presponse.getEntity（）;
是= httpEntity.getContent（）;
}否则，如果（method.equals（GET））{
//请求方法是GET
DefaultHttpClient的HttpClient =新DefaultHttpClient（）;
字符串中的paramString = URLEn codedUtils.format（PARAMS，UTF-8）;
网址+ =？ +中的paramString;
HTTPGET HTTPGET =新HTTPGET（URL）;
HTT presponse HTT presponse = httpClient.execute（HTTPGET）;
HttpEntity httpEntity = HTT presponse.getEntity（）;
是= httpEntity.getContent（）;
}
}赶上（UnsupportedEncodingException E）{
e.printStackTrace（）;
}赶上（ClientProtocolException E）{
e.printStackTrace（）;
}赶上（IOException异常E）{
e.printStackTrace（）;
}
尝试 {
的BufferedReader读卡器=新的BufferedReader（新的InputStreamReader（
是，ISO-8859-1），8）;
StringBuilder的SB =新的StringBuilder（）;
串线= NULL;
而（（行= reader.readLine（））！= NULL）{
sb.append（行+\ N）;
}
is.close（）;
JSON = sb.toString（）;
}赶上（例外五）{
Log.e（缓冲区错误，转换的结果错误+ e.toString（））;
}
//尝试解析字符串到一个JSON对象
尝试 {
jArr =新JSONArray（JSON）;
}赶上（JSONException E）{
Log.e（JSON解析器，错误分析数据+ e.toString（））;
}
//返回JSON字符串（阵列）
返回jArr;
}
}
和LoginActivity类：
包com.thevnkid93.ucebnice;
进口的java.util.ArrayList;
进口的java.util.List;
进口java.util.concurrent.ExecutionException;
进口org.apache.http.NameValuePair;
进口org.apache.http.message.BasicNameValuePair;
进口org.json.JSONArray;
进口org.json.JSONException;
进口org.json.JSONObject;
进口android.app.Activity;
进口android.content.Intent;
进口android.os.AsyncTask;
进口android.os.Bundle;
进口android.view.View;
进口android.view.View.OnClickListener;
进口android.widget.Button;
进口android.widget.EditText;
进口android.widget.Toast;
公共类LoginActivity延伸活动{
的EditText E1，E2;
按钮B1，B2;
名单＆LT;的NameValuePair＆GT; infoPost =新的ArrayList＆LT;的NameValuePair＆GT;（）;
@覆盖
保护无效的onCreate（包savedInstanceState）{
// TODO自动生成方法存根
super.onCreate（savedInstanceState）;
的setContentView（R.layout.login_layout）;
E1 =（EditText上）findViewById（R.id.login_e1）;
E2 =（EditText上）findViewById（R.id.login_e2）;
B1 =（按钮）findViewById（R.id.login_b1）;
B2 =（按钮）findViewById（R.id.login_b2）;
b1.setOnClickListener（新OnClickListener（）{
公共无效的onClick（查看为arg0）{
INT VYS = 0;
。字符串email = e1.getText（）的toString（）;
。字符串heslo = e2.getText（）的toString（）;
LoadInfo loadi =新LoadInfo（）;
尝试 {
VYS = loadi.execute（电子邮件，heslo）获得（）;
}赶上（InterruptedException异常E）{
// TODO自动生成的catch块
e.printStackTrace（）;
}赶上（为ExecutionException E）{
Toast.makeText（LoginActivity.this，XXXXXXXX，Toast.LENGTH_LONG）.show（）;
e.printStackTrace（）;
}
Toast.makeText（LoginActivity.this，+ VYS，Toast.LENGTH_LONG）.show（）;
}
}）; // TLACITKO PRIHLASENI
}
}
类LoadInfo扩展的AsyncTask＆LT;字符串，字符串，整数＆GT; {
名单＆LT;的NameValuePair＆GT; PARAMS =新的ArrayList＆LT;的NameValuePair＆GT;（）;
@覆盖
保护整数doInBackground（字符串参数... args）{
params.add（新BasicNameValuePair（电子邮件，ARGS [0]））;
params.add（新BasicNameValuePair（heslo，的args [1]））;
JSONArray jArray = JSONParser.makeHtt prequest（my_url，POST，则params）;
INT VYS = 0;
尝试 {
的JSONObject jobject = jArray.getJSONObject（0）;
VYS = jobject.getInt（vysledek）;
}赶上（JSONException E）{
VYS = 2;
e.printStackTrace（）;
}
返回VYS;
}
}
解决方案
第一件事，第一。我们需要一个更具体的信息，那么它只是不工作
您需要做的事情。
1）用一个伟大的教程。我强烈建议这个之一。
2），然后检查你的code确保你的PHP作品。有一个伟大的！测试名为<一个href="https://chrome.google.com/webstore/detail/postman-rest-client/fdmmgilgnpjigdojojpjoooidkmcomcm?hl=en"相对=nofollow>邮差。用它来测试你的PHP code。
3）组织类更好。你应该让（像我张贴的教程一样）处理网络电话和调用你创建JSON类useractions类。
这三样东西，你可以调试你的code，然后给我们一个更具体的问题，社会将最有可能能够帮助您用。
So, I'm trying to make a login activity. It uses database from mySql so I made a php webservice 1login.php. Then I have a JSONParser class with method makeHttpRequest(url,method,params) and a LoginActivity class. But there is a problem. I can not send the params to the webservice, but when I tried with GET method, it worked(with some problem with the char '@'). I want to find out how to use the Post method. Here are the codes:
PHP: (it works well, so I don't think the problem is here)
<?php
include "0conn.php";
$email =$_POST["email"];
$heslo =$_POST["heslo"];
$pass=sha1($heslo);
$query = mysqli_query($conn,"SELECT jmeno,email FROM users WHERE email='$email' AND heslo='$pass'");
$res=array();
$response=array();
if(mysqli_num_rows($query)==1){
$result=mysqli_fetch_array($query);
$res["vysledek"]=1;
$res["email"]=$result["email"];
$res["jmeno"]=$result["jmeno"];
}
else $res["vysledek"]=0;
$response[]=$res;
mysqli_free_result($query);
echo json_encode($response);
?>
The JSONParser class:
package com.thevnkid93.ucebnice;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.R.integer;
import android.os.AsyncTask;
import android.util.Log;
public class JSONParser{
static InputStream is = null;
static JSONObject jObj = null;
static JSONArray jArr=null;
static String json = "";
// function get json from url
// by making HTTP POST or GET method
public static JSONArray makeHttpRequest(String url, String method,
List<NameValuePair> params) {
// Making HTTP request
try {
// check for request method
if(method.equals("POST")){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params,"utf-8"));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method.equals("GET")){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jArr = new JSONArray(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String (Array)
return jArr;
}
}
and the LoginActivity class:
package com.thevnkid93.ucebnice;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ExecutionException;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
public class LoginActivity extends Activity{
EditText e1,e2;
Button b1,b2;
List<NameValuePair>infoPost=new ArrayList<NameValuePair>();
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.login_layout);
e1 = (EditText)findViewById(R.id.login_e1);
e2 = (EditText)findViewById(R.id.login_e2);
b1 = (Button)findViewById(R.id.login_b1);
b2 = (Button)findViewById(R.id.login_b2);
b1.setOnClickListener(new OnClickListener(){
public void onClick(View arg0){
int vys=0;
String email=e1.getText().toString();
String heslo=e2.getText().toString();
LoadInfo loadi=new LoadInfo();
try {
vys=loadi.execute(email,heslo).get();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ExecutionException e) {
Toast.makeText(LoginActivity.this, "xxxxxxxx", Toast.LENGTH_LONG).show();
e.printStackTrace();
}
Toast.makeText(LoginActivity.this, ""+vys, Toast.LENGTH_LONG).show();
}
});//TLACITKO PRIHLASENI
}
}
class LoadInfo extends AsyncTask<String, String, Integer>{
List<NameValuePair> params = new ArrayList<NameValuePair>();
@Override
protected Integer doInBackground(String... args) {
params.add(new BasicNameValuePair("email", args[0]));
params.add(new BasicNameValuePair("heslo", args[1]));
JSONArray jArray = JSONParser.makeHttpRequest(my_url, "POST", params);
int vys=0;
try {
JSONObject jobject = jArray.getJSONObject(0);
vys=jobject.getInt("vysledek");
} catch (JSONException e) {
vys=2;
e.printStackTrace();
}
return vys;
}
}
解决方案
First thing first. We need a more specific information then " it just does not work"
Things you need to do.
1) Use a great tutorial. I strongly recommend this one.
2) before you check your code make sure your php works. There is a GREAT! tester called POSTman. Test your php code with it.
3) organize your classes better. you should make (like the tutorial I posted does) a useractions class that handles the web calls and calls to the JSON class you create.
with those three things you be able to debug your code and then give us a more specific problem that the community will most likely be able to assist you with.
这篇关于从Android的Post方法不起作用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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