我想问一下，当我按下“Y”时，我将如何添加重复功能。 [英] I would like to ask how I going to add the repeat function once I press "Y"

问题描述

  //   TMA2Q3.cpp：定义控制台应用程序的入口点。  
  //    
 
  #include     stdafx.h  
   #include      stdio.h 
   #include     string.h 
  
 
  int  main（）{
  int  maxNumber =  0 ; 
 
 printf（ 按名称和ID编制：12345 \ n ）; 
 printf（  Class：3SPG1 \\\
）; 
 printf（ 此程序接受一组数字并执行排序和索引。\ n< /跨度>）; 
 printf（ 请输入要排序的数字（最多20个）：）; 
 scanf_s（ ％d，& maxNumber）; 
 
  int  * aryNumbers = NULL; 
  int  * sortedIndex = NULL; 
  int  * sortedNumbers = NULL; 
 aryNumbers = realloc（aryNumbers，maxNumber）; 
 sortedIndex = realloc（sortedIndex，maxNumber）; 
 sortedNumbers = realloc（sortedNumbers，maxNumber）; 
 
  for （ int  i =  1 ; i< = maxNumber; i ++）{
  char  y [ 2 ]; 
 itoa（i，y， 10 ）; 
 printf（ 数字键＃％s：，& y）; 
 scanf_s（ ％d，& aryNumbers [i  -   1 ]）; 
 sortedNumbers [i  -   1 ] = aryNumbers [i  -   1 ]; 
} 
 
 printf（ 数字的原始顺序为：< /跨度>）; 
  for （ int  i =  0 ; i< maxNumber; i ++）{
  char  z [ 2 ]; 
 itoa（aryNumbers [i]，z， 10 ）; 
 printf（ ％s，& z）; 
} 
 
  //  执行排序并分配 
  int  index; 
  for （ int  i =  0 ; i< maxNumber; i ++）{
 sortedIndex [i] = i +  1 ; 
  for （ int  j =  0 ; j< maxNumber; j ++）{
  if （sortedNumbers [j]> sortedNumbers [i]）{
  int  temp = sortedNumbers [j]; 
 sortedNumbers [j] = sortedNumbers [i]; 
 sortedNumbers [i] = temp; 
 sortedIndex [i] = j +  1 ; 
} 
} 
} 
 
 printf（  \ n排序的数字是：）; 
  for （ int  i =  0 ; i< maxNumber; i ++）{
  char  z [ 2 ]; 
 itoa（sortedNumbers [i]，z， 10 ）; 
 printf（ ％s，& z）; 
} 
 
  //  查找排序索引 
  for （ int  i =  0 ; i < maxNumber; i ++）{
  for （ int  j =  0 ; j< maxNumber; j ++）{
  if （aryNumbers [i] == sortedNumbers [j]）{ 
 sortedIndex [i] = j +  1 ; 
} 
} 
} 
 
  for （ int  i =  0 ; i< maxNumber; i ++）{
  char  a [ 2 ]; 
  char  b [ 2 ]; 
  char  c [ 2 ]; 
 itoa（i +  1 ，a， 10 ）; 
 itoa（aryNumbers [i]，b， 10 ）; 
 itoa（sortedIndex [i]，c， 10 ）; 
 printf（  \ n编号＃％s（％s）的索引是％s，& a，& b，& c）; 
} 
 printf（  \ n你想重复这个程序吗？（Y / N ）：）; 
 
  char 输入; 
 scanf_s（ ％d，& input）; 
 
  return   0 ; 
} 

我的尝试：



我从互联网上进行了研究，它的使用时间......循环，我试过几次，它无法工作......需要帮助和建议。非常感谢。

解决方案

您找到的建议是正确的：在或时使用做...而循环。

将你要重复的整个代码整理一遍，它会起作用：

  char  [ 100 ] inp; 
 做 
 {
 ...你的代码在这里... 
 scanf（ ％s，inp）; 
}  while （inp [ 0 ] == '  y' || inp [ 0 ] == '  Y'）; 
 返回  0 ; 

引用：

对不起老板，我对编程知识不足0。

这对我来说真的很难，我不明白循环如何工作。

希望你能帮助我。谢谢

A 而循环非常简单：

< pre lang =c ++> while （a）
{
b;
}
c;

1）如果条件 a 的计算结果为true，请输入循环。

1.1）执行一个或多个陈述 b

1.2）回到（1）
$ b $的测试b 2）如果条件 a 为假，则执行 c 。



还有一个 do ...而版本至少执行一次循环：

 做 
 {
b; 
}  while （a）; 
c; 

1）执行一个或多个语句 b

2）如果条件 a 计算结果为true，循环回（1）

3）否则，执行 c 。 br />


所有这些都在文档中......




// TMA2Q3.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include "stdio.h"
#include "string.h"


int main() {
	int maxNumber = 0;

	printf("Prepared by Name and ID: 12345 \n");
	printf("Class: 3SPG1 \n");
	printf("This program takes in a set of numbers and performs sorting and indexing. \n");
	printf("Please key in how many numbers you want to sort(max.20): ");
	scanf_s("%d", &maxNumber);

	int *aryNumbers = NULL;
	int *sortedIndex = NULL;
	int *sortedNumbers = NULL;
	aryNumbers = realloc(aryNumbers, maxNumber);
	sortedIndex = realloc(sortedIndex, maxNumber);
	sortedNumbers = realloc(sortedNumbers, maxNumber);

	for (int i = 1; i <= maxNumber; i++) {
		char y[2];
		itoa(i, y, 10);
		printf("Key in number #%s: ", &y);
		scanf_s("%d", &aryNumbers[i - 1]);
		sortedNumbers[i - 1] = aryNumbers[i - 1];
	}

	printf("The original order of the numbers are: ");
	for (int i = 0; i < maxNumber; i++) {
		char z[2];
		itoa(aryNumbers[i], z, 10);
		printf("%s ", &z);
	}

	//perform sorting and assign
	int index;
	for (int i = 0; i < maxNumber; i++) {
		sortedIndex[i] = i + 1;
		for (int j = 0; j < maxNumber; j++) {
			if (sortedNumbers[j] > sortedNumbers[i]) {
				int temp = sortedNumbers[j];
				sortedNumbers[j] = sortedNumbers[i];
				sortedNumbers[i] = temp;
				sortedIndex[i] = j + 1;
			}
		}
	}

	printf("\nThe sorted numbers are: ");
	for (int i = 0; i < maxNumber; i++) {
		char z[2];
		itoa(sortedNumbers[i], z, 10);
		printf("%s ", &z);
	}

	//find sorted index
	for (int i = 0; i < maxNumber; i++) {
		for (int j = 0; j < maxNumber; j++) {
			if (aryNumbers[i] == sortedNumbers[j]) {
				sortedIndex[i] = j + 1;
			}
		}
	}

	for (int i = 0; i < maxNumber; i++) {
		char a[2];
		char b[2];
		char c[2];
		itoa(i + 1, a, 10);
		itoa(aryNumbers[i], b, 10);
		itoa(sortedIndex[i], c, 10);
		printf("\nThe index for number #%s (%s) is %s", &a, &b, &c);
	}
	printf("\nDo you want to repeat the program?(Y/N): ");

	char input;
	scanf_s("%d", &input);

	return 0;
}



What I have tried:

I had research from internet, its ask for use while...loop, I had tried few time, its cannot work...need help and advice. Many thanks.

解决方案

The advice you found is right: use a while or do...while loop.
PUt one round the whole of the code you want to repeat, and it will work:

char[100] inp;
do
   {
   ... your code here ...
   scanf("%s", inp);
   } while (inp[0] == 'y' || inp[0] == 'Y');
return 0;

Quote:

So sorry boss, I'm 0 knowledge on programming.
It's really difficult for me, I was not understand how while loop work.
Hopefully you can help me. Thanks

A while loop is really simple:

while (a)
   {
   b;
   }
c;

1) If the condition a evaluates to true, enter the loop.
1.1) Execute the statement or statements b
1.2) Got back round to the test at (1)
2) If the condition a was false, execute c instead.

There is also a do ... while version which executes the loop at least once:

do
   {
   b;
   } while (a);
c;

1) Execute the statement or statements b
2) If the condition a evaluates to true, loop back to (1)
3) Otherwise, execute c instead.

All of this is in the documentation ...




这篇关于我想问一下，当我按下“Y”时，我将如何添加重复功能。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！