通过编程执行另一个触摸事件当一个触摸事件的Andr​​oid occures [英] Programatically execute another touch event when one touch event occures in android

问题描述

我想提出的ImageView拖放与触摸原始创建重复的实例。

I am making ImageView Drag and drop with creating duplicate instance by touching original one.

我有一个水平布局containg很多小的图像。 当我触摸它会创建它的副本实例，并将在该位置在屏幕上略有不同。

I am having one horizontal-layout containg many small images. when I touch on it it creates duplicate instance of it and puts at that position on screen slight different.

现在，我要继续触摸事件，但要完成了对原有的ImageView做第一个触摸事件，并希望启动它的重复实例的触摸事件。但出除去fingure了。

Now, I want to continue the touch event but want to finish up the first one touch event done on the original ImageView and want to start-up the touch event of duplicate instance of it. but with-out removing fingure up.

我做了以下内容：

img22.setOnTouchListener(new OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        ImageView img2 = null;

        switch (event.getActionMasked()) {
        case MotionEvent.ACTION_DOWN :
...   ...
...   ...
            Bitmap bmp2 = BitmapFactory.decodeResource(ImageListActivity.this.getResources(),
                R.drawable.img2);
            //ImageView 
            img2 = new ImageView(ImageListActivity.this);
            img2.setImageBitmap(bmp2);
            img2Param.setMargins( (rx-10-x), (ry-10-y-50), 0, 0);
            img2.setLayoutParams(img2Param);

            img2.setOnTouchListener(new OnTouchListener() {
                    @Override
                    public boolean onTouch(View v, MotionEvent event) {


                    System.out.println("   ---   img2 On Touch Called   ---");

                    RelativeLayout.LayoutParams img2Param =
                    (RelativeLayout.LayoutParams) v.getLayoutParams();
                    img2Param.setMargins((int)event.getRawX()-10, (int)event.getRawY()-60, 0, 0);
                    v.setLayoutParams(img2Param);
                    v.invalidate();
                        return true;
                    }
                });
            long downTime2 = SystemClock.currentThreadTimeMillis(),
                    eventTime2 = SystemClock.currentThreadTimeMillis() + 10;
            float x2 = 0.0f, y2 = 0.0f;
            int metaState2 = 0;
            MotionEvent motionEvent2 = MotionEvent.obtain(
                    downTime2, eventTime2, MotionEvent.ACTION_POINTER_1_UP, x2, y2, 1);
            v.dispatchTouchEvent(motionEvent2);

            long downTime = SystemClock.currentThreadTimeMillis(),
                    eventTime = SystemClock.currentThreadTimeMillis();// + 5000;
            float x1 = 0.0f, y1 = 0.0f;
                int metaState = 0;
            MotionEvent motionEvent = MotionEvent.obtain(
                    downTime, eventTime, MotionEvent.ACTION_MOVE, x1, y1, 1);
            img2.onTouchEvent(motionEvent);
...    ...
...    ...

任何一个可以给我知道关于继续触摸事件，改变ImageView的实例。

推荐答案

这听起来像你想要做的就是点击Image1的，有这样的行动创建一个IMAGE2，继续触摸手势，如果它被点击IMAGE2？

It sounds like what you want to do is click "Image1", have this action create an "Image2" and continue the touch gesture as if it was clicked on "Image2"?

这可能是一个更好的主意，有一个触摸表面 - 以上这些观点的捕捉触摸事件，然后分层一条无形的视图执行的操作需要 - 这将意味着你可以继续你的手势关图像而无需创建一个新的姿态。

Instead of doing this it might be a better idea to have a Touch Surface - An invisible view layered above these view's which captures the touch event and then performs the actions as needed - this will mean you can continue your gesture "off" the image without creating a new gesture.

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