代码是未完成的但是从我到目前为止我一直得到一个错误，指出“没有运算符'='匹配这些操作数” [英] The code is unfinished but from what I have so far I keep getting an error stating that "no operator '=' matches these operands"

问题描述

#include <iostream>
#include <string>
using namespace std;

class Movie
{
private:
	string name;
	string director;
public:
	Movie()
	{
		name = "Movie";
		director = "Director";
	}
	Movie(string n, string d)
	{
		name = n;
		director = d;
	}
	void setName(string n)
	{
		name = n;
	}
	void setDirector(string d)
	{
		director = d;
	}
	string getName()
	{
		return name;
	}
	string getDirector()
	{
		return director;
	}
	void DisplayData(Movie data[], int size)
	{
		cout << "Movie list: ";
		for (int c = 0; c < size; c++)
		{
			cout << name[c] << " ";
		}

		cout << endl;
	}
	void BubbleSort(Movie data[], int size)
	{
		string temp;
		bool swap;
		do
		{
			swap = false;
			for (int c = 0; c < size - 1; c++)
			{
				if (data[c].getName() > data[c+1].getName())
				{
					temp = data[c];
				}
			}
		} while (swap = true);
	}

};

我的尝试：



我尝试过不同的东西，但无济于事。

What I have tried:

I've tried different things but to no avail.

推荐答案

{
    temp = data[c];
}

你试图将'temp'（一个字符串）分配给一个电影的实例类。您需要将其分配给类中name字符串的副本。你可以通过为类创建一个'='运算符，或者通过'getName'或其他方式创建。

You are trying to assign 'temp' (a string) to an instance of a Movie class. You need to assign it to a copy of the 'name' string in the class. You can do so by creating an '=' operator for the class, or through 'getName' or another way if you wish.

你的而陈述错误：

Your while statement is wrong:

do
		{
			swap = false;
			for (int c = 0; c < size - 1; c++)
			{
				if (data[c].getName() > data[c+1].getName())
				{
					temp = data[c];
				}
			}
		} while (swap = true);

你要分配 true 到 swap ，而不进行比较。 '等于'是==，而不是=。

You're assigning true to swap, not making a comparison. 'Equal to' is ==, not =.

嘿，这是C ++，你可以更好地替代数组和冒泡排序。

Hey man, it is C++ and you far better alternatives to arrays and bubble sort.

#include <vector>
#include <algorithm>
#include <iostream>
#include <string>
using namespace std;

class Movie
{
private:
  string name;
  string director;
public:

  Movie(string n="Movie", string d="Director"):name(n), director(d){}

  void setName(string n)
  {
    name = n;
  }
  void setDirector(string d)
  {
    director = d;
  }
  const   string getName() const
  {
    return name;
  }
  const string getDirector() const
  {
    return director;
  }
};

ostream & operator << (ostream & os, const Movie & movie)
{
  os << movie.getName();
  return os;
}

int main()
{
  vector< Movie > mv{ Movie("Foo", "boo"), Movie("Goo"), Movie("AAA", "BBB")};

  cout << "list of movies: ";
  for ( const auto & m : mv)
    cout << m << " ";
  cout << endl;

  sort( mv.begin(), mv.end(), [](const Movie & m1, const Movie & m2) {return (m1.getName() < m2.getName());});

  cout << "sorted list of movies: ";
  for ( const auto & m : mv)
    cout << m << " ";
  cout << endl;
}

这篇关于代码是未完成的但是从我到目前为止我一直得到一个错误，指出“没有运算符'='匹配这些操作数”的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！