如何在C中使用w来读取数字直到-1，并计算用户输入的偶数和奇数？ [英] How to wap in C to read a number until -1 is encountered and count how many even and odd number entered by user?

问题描述

在C编程，控制语句章节。



我尝试过：

in C programming ,control statements chapter.

What I have tried:

/*I have done*/
int num,even=0,odd=0;

do{printf("enter number")
scanf("%d",&num);
if(num÷2==0)
even+=1;
else odd+=1;
printf("even number %d",even);
printf("odd number %d",odd);

推荐答案

学会正确缩进代码，显示其结构，有助于阅读和理解。它还有助于发现结构错误。

Learn to indent properly your code, it show its structure and it helps reading and understanding. It also helps spotting structures mistakes.

/*I have done*/
int num,even=0,odd=0;
do{
  printf("enter number")  // ; is missing here
  scanf("%d",&num);
  if(num÷2==0)
    even+=1;
  else 
    odd+=1;
// } is missing here
// end of loop is missing here
printf("even number %d",even);
printf("odd number %d",odd);

专业程序员的编辑器具有此功能，其他功能包括括号匹配和语法高亮。

Notepad ++主页 [ ^ ]

ultraedit [ ^ ]



请注意，您的代码将计数-1作为输入值。

Professional programmer's editors have this feature and others ones such as parenthesis matching and syntax highlighting.
Notepad++ Home[^]
ultraedit[^]

Note that your code will count -1 as an input value.

这应该可以解决问题：

This should do the trick:

int num = 0, even = 0, odd = 0;

do
{
    printf( "enter number (-1 exits):" );
    scanf( "%d", &num );
    if ( num != -1 )
    {    
        if ( num & 0x01 ) odd++;
        else              even++;
    };
    
} while ( num != -1 );
    
printf( "even number %d", even );
printf( "odd number %d",  odd );

我希望能帮到你。

-Doug

I Hope that helps you.
-Doug

首先你需要一些< a href =http://www.cplusplus.com/doc/tutorial/control/>关于do-while循环的教程。



生成的代码可能如下所示：

At first you need some tutorial about the do-while loop.

The resulting code could look like this:

int count = 0;
do {
count++;
if( ... )
  break;//quick leave loop
}while( num!= -1;

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