获取要检查和计算的偶数值 [英] Get even values to be checked and counted
问题描述
我遇到的问题是程序识别数字何时均匀以及有多少数字。我有我的int，但它目前什么都不做，但确实有效（显然是0）。了解我，我的源代码可能存在很多问题。
我尝试过：
公共类ArraysAsArguments
{
随机r = new Random（）;
int [] []数组;
int row;
int col;
static int count;
static int [] [] myArray;
static int value;
static ArraysAsArguments c = new ArraysAsArguments（）;
static int evenNum;
public int [] [] createArray（int rSize，int cSize）
{
array = new int [rSize] [cSize] ;
for（row = 0; row< array.length; row ++）
{
for（col = 0; col< array [0] .length; col ++）
{
array [row] [col] = r.nextInt（100）+ 1;
}
}
返回数组;
}
public void printArray（int [] [] array）
{
for（row = 0;行< array.length;行++）
{
for（col = 0; col< array [0] .length; col ++）
{
System.out.print（array [row] [col] +\t）;
}
System.out.println（\\ \\ n）;
}
}
public int countInstance（int [] [] array， int search）
{
count = 0;
for（row = 0; row< array.length; row ++）
{
for（col = 0; col< array [0] .length; col ++）
{
if （array [row] [col] == search）
{
count ++;
}
}
}
返回计数;
}
/ **
* @param args命令行参数
* /
public static void main（String [] args ）
{
myArray = c.createArray（25,1）;
c.printArray（myArray）;
System.out.println（有+ evenNum +偶数）;
}
}
I'm having an issue with the program recognizing when a number is even and how many there are. I have my int but it currently does nothing but does work (obviously comes up with 0). Knowing me, there is probably a bunch of issues with my source code.
What I have tried:
public class ArraysAsArguments
{
Random r = new Random();
int[][] array;
int row;
int col;
static int count;
static int[][] myArray;
static int value;
static ArraysAsArguments c = new ArraysAsArguments();
static int evenNum;
public int[][] createArray(int rSize, int cSize)
{
array = new int[rSize][cSize];
for(row = 0; row < array.length; row++)
{
for(col = 0; col < array[0].length; col++)
{
array[row][col] = r.nextInt(100) + 1;
}
}
return array;
}
public void printArray(int[][] array)
{
for(row = 0; row < array.length; row++)
{
for(col = 0; col < array[0].length; col++)
{
System.out.print(array[row][col] + "\t");
}
System.out.println("\n");
}
}
public int countInstance(int[][] array, int search)
{
count = 0;
for(row = 0; row < array.length; row++)
{
for(col = 0; col < array[0].length; col++)
{
if(array[row][col] == search)
{
count++;
}
}
}
return count;
}
/**
* @param args the command line arguments
*/
public static void main(String[] args)
{
myArray = c.createArray(25, 1);
c.printArray(myArray);
System.out.println("There are " + evenNum + " even numbers");
}
}
推荐答案
您声明一个名为evenNum的变量。您打印出一个名为evenNum的变量。但无处为变量evenNum赋值。
你会想要类似于你的countInstance功能。除了测试数组元素是否等于指定值，你需要测试它是否是偶数。
最简单的方法是使用模运算符：
使用Modulo（％）运算符 - Java教程| Dream.In.Code [ ^ ]
You declare a variable calledevenNum. You print out a variable calledevenNum. But nowhere do you assign a value to the variableevenNum.
You'll want something similar to yourcountInstancefunction. Except instead of testing whether the array element is equal to a specified value, you'll need to test whether it's even.
The simplest way to do that would be using the modulo operator:
The Use Of The Modulo (%) Operator - Java Tutorials | Dream.In.Code[^]
import java.io. *;
class evenNumber
{
public static void main（String args []）
{
BufferedReader br = new BufferedReader（new InputStreamReader（System.in））;
int num;
num = Integer.parseIntbr.readLine（）;
if（num％2 == 0）
{
System.out.println（数字是偶数）;
}
其他
{
System.out.println（数字不均匀）;
}
}
}
如果有很多数字，那么输入那么多数字并用模数运算符检查......
import java.io.*;
class evenNumber
{
public static void main(String args[])
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int num;
num=Integer.parseIntbr.readLine();
if(num%2==0)
{
System.out.println("The number is even");
}
else
{
System.out.println("The number is not even");
}
}
}
If there are many numbers,then enter that many numbers and check with the modulous operator...
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