我如何获得激活的第一选择？ [英] How do I get the first choice to activate?

问题描述

import sys
from random import randint


print("Choose: Y/N")
def main():
    user_input = str(input("y/n"))
    Choice = user_input
    if Choice == "y":
        loop()
    if Choice == "n":
        print("goodbye")
        quit()

counter = 0
trials = 0

def loop():
    global counter
    global trials
    nPeople = int(input("Enter the Number of People in the Room: "))
    myBday = randint(1,365)
    userInput = "y"
    while userInput.lower() == "y":
        for i in range (1, nPeople+1):
            if myBday == randint(1,365):
                counter += 1
                break
    trials += 1
    print(counter/trials)
    main()
    loop()
    
if __name__ == "__main__":
    loop()

我无法获得第一个主要选择来提示回复。



我尝试了什么：



我尝试引入更多变量。并改变一切。

I can't get the First "Main" choice to prompt a response.

What I have tried:

I have tried introducing more variables. and changing everything around.

推荐答案

你的测试结尾是错误的， __ name __ 只等于__ main __以交互方式运行，或从命令行运行。它应该是：

Your test at the end is wrong, __name__ is only equal to "__main__" when running interactively, or from the command line. It should be:

if __name__ != "__main__":

此外还有打印行

Also the print line

print("Choose: Y/N")

应位于主函数内部，就在输入请求之前，因此用户知道它正在等待输入。

should be inside your main function, just before the input request, so the user knows that it is waiting for input.

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