创建一个你想再玩Y / N？选项 [英] Create a would you like to play again Y/N? Option

问题描述

我在实施你想要再次玩的问题然后如果玩家进入Y然后重新启动整个游戏。我只需要添加另一个while语句，当我这样做时就把它搞砸了。



我尝试了什么：



包journal.pkg3c;



/ **

*

* @author stephenwessels

* /

import java.util.Scanner;

import java.util.Random;

公共类Journal3C

{



/ **

* @param args the the命令行参数

* /

public static void main（String [] args）

{

Scanner in = new Scanner（System.in）;

Random rnd = new Random（）;



System.out.println（猜一个1到10之间的数字）;

int count = 1;

int guess = in.nextInt（）;

int num = rnd .nextInt（10）+ 1;



while（guess！= num）

{

系统。 Ø ut.println（猜一个1到10之间的数字）;

guess = in.nextInt（）;

count ++;

}

System.out.println（需要+计数+猜测才能正确猜测）;

System.out。 println（你想再玩Y / N吗？）;



}

}

I'm having issues with implementing a would you like to play again and then if the player enters Y then it restarts the whole game. I just need to add another while statement in when I do it just messes it all up.

What I have tried:

package journal.pkg3c;

/**
*
* @author stephenwessels
*/
import java.util.Scanner;
import java.util.Random;
public class Journal3C
{

/**
* @param args the command line arguments
*/
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
Random rnd = new Random();

System.out.println("Guess a number between 1 and 10");
int count = 1;
int guess = in.nextInt();
int num = rnd.nextInt(10) + 1;

while(guess != num)
{
System.out.println("Guess a number between 1 and 10");
guess = in.nextInt();
count++;
}
System.out.println("It took " + count + " guesses to guess correctly");
System.out.println("Would you like to play again Y/N?");

}
}

推荐答案

你可以这样做：

You can do it like this:

Boolean play = true;
while (play) {
    // game code here

    System.out.println("Would you like to play again Y/N?");
    play = in.nextLine().trim().equalsIgnoreCase("y"); // "y" will set 'play' to 'true', anything else will set it to 'false'
}

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