的Andr​​oid（2.1分）：从名称字符串载入图像 [英] Android (min 2.1): load images from name string

问题描述

我希望能够从RES /绘制动态加载图像。我不知道有多少文件会有，但我知道他们将被命名约定为image_N，其中N是连续的整数。这是可能的新图像将应用程序运行时进行上传。

I want to be able to load images dynamically from res/drawable. I don't how many files there will be, but I do know they will be named by convention as "image_N", where N is sequential integer. It is possible that new images will be uploaded while the app is running.

我的code是基本

Resources rs = getResources();
String imgName = "android.resource://" + this.getPackageName() + "/drawable/image_" + i;
int imgID = rs.getIdentifier(imgName , null, getPackageName());

if (imgID != 0)
{
    Drawable d = rs.getDrawable(imgID);
    //etc.
}

但 imgID 返回总是 0 。

我也试过另一种方法

String imgName = "android.resource://" + this.getPackageName() + "/drawable/image_" + i;
b = BitmapFactory.decodeFile(imgName);
if (b != null)
//etc

但 B 总是空。

我知道有该文件夹中的文件与正确的名字，因为我放了几个在那里。不知道我在做什么错。任何帮助将大大AP preciated！

I know there are files in the folder with the right names because I put a few there. Not sure what I'm doing wrong. Any help would be greatly appreciated!

推荐答案

我想你搞错编译资源，里面的文件夹的文件。在Android中，资源是静态的，据我所知。一旦编译，你无法通过内部绘制文件夹中文件拖放添加新的资源，就没有标识的新文件。 您应该使用一个文件夹中的数据或更好的要求Android的API与getFilesDir（）或类似的东西。

I think you've mistaken compiled resources with files inside folders. In Android, resources are static as far as I know. Once compiled you can't add new resources by dropping files inside "drawable" folder, there would be no IDs for new files. You should use a folder in DATA or better ask Android API with getFilesDir() or something similar.

有关更多信息，请查看>> 这里

For more info, take a look >>here

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