我在尝试运行PHP数据库代码时收到两条错误消息。 [英] I get two error messages while trying to run my PHP database code.
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问题描述
（！）警告：mysqli_num_rows（）要求参数1为mysqli_result，第18行的/var/www/2909kher/entabell/detaljer.php中给出布尔值
和
（！）警告：mysqli_fetch_array（）要求参数1为mysqli_result，在/ var /中给出布尔值www / 2909kher / entabell / detaljer.php第20行
< ;！doctype html>
< html>
< body>
Dette er detaljer.php< br>
<？php
include（'oppkobling.php'）;
// $ by = $ _POST [''];
// echo（$ by）;
//滞后SQL设置
$ query ='SELECT * FROM rikestemennesker WHERE id ='。$ _ GET ['id'];
//Kjørspørringen
$ resultat = mysqli_query（$ db，$ query）;
// Lagre antall海报som er funnet
$ antall = mysqli_num_rows（$ resultat）;
$ rad = mysqli_fetch_array（$ resultat）;
echoNavn：。$ rad ['Navn']。< img src ='./bilder/'\".$rad['Bilde'].\"><br> ;;
echoLand：。$ rad ['Land']。< br>;
echoNettoformue：。$ rad ['Nettoformue']。< br>;
echoKilde：。$ rad ['Kilde']。< br>;
？>
< / body>
< / html>
我尝试过：
我已经尝试修复了和，并定义了结果和varibles
解决方案
by =
_POST [''];
// echo（
by）;
//滞后SQL设置
( ! ) Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in /var/www/2909kher/entabell/detaljer.php on line 18
and
( ! ) Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /var/www/2909kher/entabell/detaljer.php on line 20
<!doctype html>
<html>
<body>
Dette er detaljer.php <br>
<?php
include('oppkobling.php');
//$by = $_POST[''];
//echo($by);
// Lag SQL-setning
$query = 'SELECT * FROM rikestemennesker WHERE id = '.$_GET['id'];
// Kjør spørringen
$resultat = mysqli_query($db, $query);
// Lagre antall poster som er funnet
$antall = mysqli_num_rows($resultat);
$rad = mysqli_fetch_array($resultat);
echo "Navn: ".$rad['Navn']."<img src = './bilder/'".$rad['Bilde']."><br>";
echo "Land: ".$rad['Land']."<br>";
echo "Nettoformue: ".$rad['Nettoformue']."<br>";
echo "Kilde: ".$rad['Kilde']."<br>";
?>
</body>
</html>
What I have tried:
I've tried fixing alle the " and 'is, and defined the results and varibles
解决方案
by =
_POST['']; //echo(
by); // Lag SQL-setning
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