将0附加到C中的整数 [英] Appending 0 to an integer in C

问题描述

我的整数为123.

如何将0加到此并获得0123。

我不想只打印。我想永久追加0.

怎么办？

提前感谢



我的尝试：



我无法尝试。我可以像％04d那样打印但是无法分配为值

解决方案

你不能。

数字不会像：它们存储在一个具有固定位数的存储单元中，通常是8：8位（字节），16位（短），32位（int或int32），64位（long或int64）的倍数）。在该存储器中，所有位总是被使用 - 它们总是为零或一个，具体取决于存储的数量。

将数字1存储在16位（短）值中 - 因为这里写的比32位整数更容易 - 你会得到：

 0000000000000001 

123你会得到

 0000000001111100 

正如您所看到的，您的号码中已经有大量前导零值！



数字（无论大小或类型 - 浮点数，双精度数和十进制数值也存储为位值）没有前导零的概念，它们仅在应用格式时才可用转换为字符串时的数字（通常用于呈现给用户）。



您不能将前导零添加到保留为整数的整数：0123与000000000000123或123

<相同的整数br>

引用：

我无法尝试。我可以像％04d那样打印它但不能指定为值

你只能用字符串来做，这就是数字的表示。例如

  int  a =  123 ; 
  char  sa [ 5 ]; 
 snprintf（sa， sizeof （sa）， ％04D，一个）; 

Hi,

I have an integer as 123.
How to append 0 to this and get 0123 .
I dont want just printing. I want to permanently append 0.
How to do?
thanks in advance

What I have tried:

I am unable to try. I can print it just like %04d but unable to assign as value

解决方案

You can't.
Numbers aren't stored like that: they are stored in a memory location which has a fixed number of bits, normally a multiple of 8: 8 bits (byte), 16 bits (short), 32 bits (int, or int32), 64 bits (long or int64). And in that memory, all the bits are always used - they are always either a zero or a one depending on the number being stored.
To store the number 1 in a 16 bit (short) value - becuase it's easier to write down here than a 32 bit integer - you would get:

0000000000000001

For 123 you would get

0000000001111100

As you can see, you already have a significant number of "leading zero" values in your number!

Numbers (regardless of size, or type - float, double, and decimal values are stored as bit values as well) do not have a concept of leading zeros, they are only every available when formatting is applied to a number when it is converted to a string (normally for presentation to a user).

You cannot add a "leading zero" to a integer which is preserved while it remains a number: 0123 is the same integer as 000000000000123 or 123

Quote:

I am unable to try. I can print it just like %04d but unable to assign as value

You can only do it with a string, that is the representation of the number. For example

int a = 123;
char sa[5];
snprintf(sa, sizeof(sa), "%04d",a);

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