嗨，我正在登录并注销代码。 [英] Hi, I am making a sign in and sign out code.
问题描述
我已经弄明白了，主要的错误是在注册过程中检查相同的用户名是不行的。请帮助
我尝试过：
I've figured out everything, the main error is that the check for same username during sign up is not working. Please help
What I have tried:
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
#include<stdlib.h>
#include<time.h>
#include <cstdlib>
#include "conio.h"
using namespace std;
int check(string username)
{
cin >> username;
string data1, data2;
ifstream infile;
infile.open("profile.txt", ios::app);
getline(infile, data1);
if (username == data1)
{
cout << "Username exits" << endl;
cout << "Enter new username: ";
cin >> username;
return check(username);
}
else
{
}
}
int main()
{
int z;
FIRST:
cout << "Press 1 to Create Account" << endl; cout << "Press 2 to Log In " << endl; cout << "your choice: ";
VALID: cin >> z;
switch (z)
{
case 1:
{
string name, pas, repas;
cout << "Enter Your username:";
cin >> name;
check(name);
cout << "Enter Password(Atleast 5 characters) :";
START1: cin >> pas;
if (pas.length() < 5)
{
cout << "Enter a password of atleast 5 characters : ";
goto START1;
}
else
cout << "Re-write Password to confirm:";
START2: cin >> repas;
if (repas != pas)
{
cout << "Re-Enter the Password !";
goto START2;
}
else
cout << "Profile Created With the User Name " << name << endl; // cout on the console
ofstream myfile;
myfile.open("profile.txt",ios::app);
myfile << name << endl;
myfile << pas << endl;
myfile.close();
_getch();
system("CLS");
goto FIRST;
}
case 2: // For logging in
{
system("CLS");
cout << "Welcome to Login screen\n\m";
char pass[32];
string name, pas;
START3:
cout << "Enter Username:";
cin >> name;
string data1, data2;
ifstream infile;
infile.open("profile.txt",ios::app);
getline(infile, data1);
if (name != data1)
{
cout << "Invalid User Name.Try Again\n";
goto START3;
}
else
cout << "User Name Found\n";
cout << "Enter Password : ";
int i = 0;
char a;
for (i = 0;;)
{
a = _getch();
if ((a >= 'a'&&a <= 'z') || (a >= 'A'&&a <= 'Z') || (a >= '0'&&a <= '9'))
{
pass[i] = a;
++i;
cout << "*";
}
if (a == '\b'&&i >= 1)
{
cout << "\b \b";
--i;
}
if (a == '\r')
{
pass[i] = '\0';
break;
}
}
getline(infile, data2);
START4: if (pass == data2)
{
cout << "You are Logged In";
_getch();
}
else
{
cout << "Invalid Password\nEnter Again:";
char pass[32];
cout << "Enter Password : ";
int i = 0;
char a;
for (i = 0;;)
{
a = _getch();
if ((a >= 'a'&&a <= 'z') || (a >= 'A'&&a <= 'Z') || (a >= '0'&&a <= '9'))
{
pass[i] = a;
++i;
cout << "*";
}
if (a == '\b'&&i >= 1)
{
cout << "\b \b";
--i;
}
if (a == '\r')
{
pass[i] = '\0';
break;
}
}
goto START4;
}
infile.close();
break;
}
default:
{
cout << "Please Enter Valid Number !";
goto VALID; }
}
}
推荐答案
int check（字符串用户名）
{
cin>>用户名;
字符串数据1，数据2;
ifstream infile;
infile.open（profile.txt，ios :: app）; //< - 你要将什么附加到输入文件？
getline（infile，data1）;
if（username == data1）
{
cout<< 用户名退出<< endl;
cout<< 输入新用户名：;
cin>>用户名;
返回检查（用户名）; //< - 以递归方式调用函数（文件一次又一次打开）不是一个好主意 < br $>
}
其他
{
}
}
int check(string username)
{
cin >> username;
string data1, data2;
ifstream infile;
infile.open("profile.txt", ios::app); //<-- What are you going to append to a input file?
getline(infile, data1);
if (username == data1)
{
cout << "Username exits" << endl;
cout << "Enter new username: ";
cin >> username;
return check(username);//<-- it is NOT a good idea to call the function recursively (the file is open again and again)
}
else
{
}
}
我的建议：执行检查功能只是为了检查，然后再问一遍（在调用代码中）用户输入用户名如果失败。
我的一般建议：不要使用转到，使用 C ++ 功能。
My advice: implement the check function simply for checking, then ask again (in the calling code) the user to enter the username if it fails.
My general advice: don't use goto, use the C++ features.
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