C动态内存分配 [英] C dynamic memory allocation

问题描述

void main()
{
	long int *ptr;
	clrscr();
	ptr=(long int*)malloc();
	*ptr=123456789;
	printf("%ld",*ptr);
	getch();
}

here I have not defined the size of malloc than also
it printing what is the reason

What I have tried:

output on the console is 123456789

推荐答案

引用：

这里我还没有定义malloc的大小比

它打印的原因是什么

here I have not defined the size of malloc than also
it printing what is the reason

检查动态内存分配是你的职责，正确使用malloc（）是你的责任。

C会接受任何事情直到它崩溃。



建议：阅读malloc（）文档。

Checking the dynamic memory allocation is your duty, making proper usage of malloc() is your responsability.
C will accept anything until it crash.

Advice: read malloc() documentation.

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