为什么处理程序:: postDelay使UI冻结 [英] Why does Handler::postDelay make UI frozen

问题描述

我有这个code。我不知道为什么postDelay使UI冻结在这种情况下。我想在100毫秒deley了Runnable将运行在4000毫秒运行。

I have this code. I don't know why postDelay make UI frozen in this case. I want the Runnable will run after 100 miliseconds deley and run in 4000 miliseconds.

package com.delaythread;

import android.app.Activity;
import android.os.Bundle;
import android.os.Handler;
import android.os.Message;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.ProgressBar;

public class MyNeedActivity extends Activity implements OnClickListener {

    private ProgressBar progressBar;
    private final Handler handler = new Handler() {
        @Override
        public void handleMessage(final Message msg) {
            super.handleMessage(msg);
            progressBar.setVisibility(ProgressBar.INVISIBLE);
        }
    };

    @Override
    public void onClick(final View v) {
        if(v.getId() == R.id.button1) {
            /* This call doesn't make ProgressBar frozen.
            final Thread t = new Thread(new MyRunnable());
            t.start();
            progressBar.setVisibility(ProgressBar.VISIBLE);
             */

            // This makes ProgressBar frozen in 4000 miliseconds.
            final boolean b = handler.postDelayed(new MyRunnable(), 100);
            if(b) {
                progressBar.setVisibility(ProgressBar.VISIBLE);
            }
        }
    }

    /** Called when the activity is first created. */
    @Override
    public void onCreate(final Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        ((Button)findViewById(R.id.button1)).setOnClickListener(this);
        progressBar = (ProgressBar)findViewById(R.id.progressBar1);
    }

    private class MyRunnable implements Runnable {
        @Override
        public void run() {
            sleep();
        }

        private void sleep() {
            try {
                Thread.sleep(4000);
                handler.sendEmptyMessage(0);
            } catch (final InterruptedException e) {
                e.printStackTrace();
            }
        }
    }

}

更新：其实我要的是AsyncTask的后的延迟时间执行，所以我这样做，因为这答案<一个href="http://stackoverflow.com/questions/4177409/java-android-how-to-start-an-asynctask-after-3-seconds-of-delay">Java/android如何延时3秒后启动AsyncTask的？。他说，我应该用处理器和Runnable接口。

Update: Actually what I want is AsyncTask executes after a delay time, so I do as this answer Java/android how to start an AsyncTask after 3 seconds of delay?. He said I should use Handler and Runnable.

推荐答案

以下应满足您的需要。

private final Handler handler = new Handler() {
    @Override
    public void handleMessage(final Message msg) {
        super.handleMessage(msg);
        //start Asyntask here. progress show/hide should be done in asynctaswk itself.
    }
};

@Override
public void onClick(final View v) {
    if(v.getId() == R.id.button1) {

        final boolean b = handler.postDelayed(new MyRunnable , 1000);

    }
}

private class MyRunnable implements Runnable {
    @Override
    public void run() {
        handler.sendmessage(0);
    }
}

}

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