字符数 [英] Number of characters

问题描述

hi
我必须写一个程序来获取一个字符串并告诉它的字符数。

就像我的字符串是aaabb，程序的输出应该是：

a：3

b：2





idk怎么写：（< br $> b $ b

我的尝试：

hi I have to write a program that gets a string and tells the number of its characters .
like my string is "aaabb" , the program's output should be :
a : 3
b : 2


idk how to write it :(

What I have tried:

#include<stdio.h>
int main()
{
	char a[50],ch;
	int i,j,n=0;
	printf("enter your string :\t");
	gets(a);
	for(i=0;a[i]!='\0';i++){
		for(j=0;a[j]!='\0';j++){
			if(a[i]==a[j])
			n++;
		}
	printf(" %c : %d \n",j,n);
}	
}

推荐答案

很少有修改可以完成这项工作。

Few modifications should do the job.

#include<stdio.h>
int main()
{
	char a[50],ch;
	int i,j,n=0;
	printf("enter your string :\t");
	gets(a);
	for(i=0;a[i]!='\0';i++){
                n=0; //reset the count for next character in queue
		for(j=0;a[j]!='\0';j++){
			if(a[i]==a[j])
			n++;
		}
	   printf(" %c : %d \n",i,n);//show i instead of j
        }	
}

当你为字符串中的每个字符进行迭代而不检查重复时，你仍然会看到重复的行。为了解决这个问题，您可以应用逻辑来创建一个具有唯一字符的字符串，并且您需要将其用于外部循环（i）。



查看以下链接以获取有关的帮助那个 -

C程序删除字符串中的所有重复字符 - Codeforwin [ ^ ]

删除给定字符串中的所有重复项 - GeeksforGeeks [ ^ ]



跳，它有帮助：）

You'll still be seeing duplicate lines as you are iterating for each characters in the string without checking for duplicates. To overcome this, you can apply logic to have a string with unique characters and that you need to use for outer loop (i).

Check following links for help regarding that-
C program to remove all repeated characters in a string - Codeforwin[^]
Remove all duplicates from a given string - GeeksforGeeks[^]

Hop, it helps :)

这篇关于字符数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！