如何在字符串中的单词末尾实现正则表达式 [英] How do I implement a regular expression at the end of a word in a string
问题描述
我需要帮助才能在字符串上实现正则表达式。
就像我有一个像这样的字符串'safsdfsd $ sdfsdf $ fasdf $ sdfdzs $'它应该用#替换$。
我做了类似这样的工作
x.replace(/ [$] / g,'#');
但我想要好像如果$出现在开头它应该用#替换它,如果$在一个单词的末尾,它应该替换为##
所以我的字符串应该从'fgsdfg $ sdfsdgf $ sdfas $ dgfdg $'变为'fgsdfg#sdfsdgf ## sdfas #dgfdg ##'
什么我试过了:
这是我试过的代码
x.replace(/ [$] / g,'#');
sdfsdf
fasdf
sdfdzs
I need help on implementing regex on a string.
Like if I have a string like this 'safsdfsd $sdfsdf$ fasdf $sdfdzs$' it should replace the $ with #.
I did something like this and it works
x.replace(/[$]/g,'#');
But I want it to be like if the $ is present at the beginning it should replace it with # and if the $ is at the end of a word it should replace with ##
So my string should go from 'fgsdfg $sdfsdgf$ sdfas $dgfdg$' to 'fgsdfg #sdfsdgf## sdfas #dgfdg##'
What I have tried:
Here's the code I tried
x.replace(/[$]/g,'#');
sdfsdf
fasdf
sdfdzs
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