我如何在Python中解决这个问题 [英] How do I you solve this in Python
问题描述
1.'''写一个函数数字（lst），它返回一个长度等于列表lst的列表，并且对于每个索引i，如果lst的索引i中的值是一个数字（如一个int，或一个包含小写的英文名称的字符串，大写或两者的混合），然后新列表将在同一索引中包含表示该数字的整数。 （列表lst只能包含数字类型和字符串。）如果lst的索引i中的值不是数字，则新列表将在索引i中包含值None。
2。 '''如果一个字符串不包含任何一对连续的元音，也不包含任何一对连续的辅音，则该字符串是交替的。
在英语中的26个字母中，我们考虑a / A， e / E，i / I，o / O和u / U是元音，我们认为其余21个字母是辅音（特别是我们认为'y'是辅音）。
写一个函数alternate（s），如果字符串是交替的，则返回True，否则返回False
3''''编写一个函数查询（q，L），它接受一个非空字符串q和一个字符串L列表，并返回L中包含q作为子字符串的字符串索引列表。
我尝试过的事情：
我不知道怎么样去关于问题...
1.'''Write a function digits(lst) that returns a list having length equal to the list lst, and such that, for each index i, if the value in index i of lst is a digit (either as an int, or as a string containing the english name of the digit in lower case, in upper case or in a mix of the two), then the new list will contain in the same index i the integer representing that digit. (The list lst can only contain numerical types, and strings.) If the value in index i of lst is not a digit, then the new list will contain in index i the value None.
2.'''A string is alternating if it does not contain any pair of consecutive vowels, nor any pair of consecutive consonants.
Out of the 26 alphabetical letters in the english language, we consider a/A, e/E, i/I, o/O and u/U to be vowels, and we consider the remaining 21 letters to be consonants (in particular, we consider 'y' to be a consonant).
Write a function alternate(s) that, given an alphabetical string s, returns True if the string is alternating and False otherwise.
3.'''Write a function query(q, L) that takes a non-empty string q, and a list of strings L, and returns the list of indices of the strings in L that contain q as a substring.
What I have tried:
I don't know how to go about the questions...
推荐答案
我如何解决这在Python中
How do I you solve this in Python
随着工作！
多么粗鲁，你的主要工作是粘贴你的作业，你没有表现出任何工作，你没有问题，你只是想要我们做你的家庭工作。
我们不做你的家庭工作。
HomeWork不会测试你的技能，乞求别人去做做你的工作，它会让你思考并帮助你的老师检查你对你所学课程的理解，以及你应用它们时遇到的问题。
你的任何失败都会帮助你的老师发现你的弱点并设定补救措施。
你的任何失败都会帮助你了解什么有效，什么无效，被称为'试错'学习。
所以，试一试，重读课程并开始工作。如果您遇到特定问题，请显示您的代码并解释这个问题，我们可能会提供帮助。
作为程序员，您的工作是创建算法解决特定问题，你不能依赖别人永远为你做，所以有一段时间你必须学会如何。而且越快越好。
当你要求解决方案时，就像试图通过培训其他人来学习开车一样。
创建算法基本上是找到数学并做出必要的调整以适应你的实际问题。
发展的概念就像这个词所暗示的那样：系统地使用科学和满足特定目标或要求的技术知识。 BusinessDictionary.com [ ^ ]
这与有一个不一样快速谷歌并放弃，如果我找不到正确的代码。
With work !
How rude, Your main effort is pasting your assignment, you show no work, you have no question, you just want us to do your HomeWork.
We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help your teacher spot your weaknesses and set remedial actions.
Any failure of you will help you to learn what works and what don't, it is called 'trial and error' learning.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.
As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.
The idea of "development" is as the word suggests: "The systematic use of scientific and technical knowledge to meet specific objectives or requirements." BusinessDictionary.com[^]
That's not the same thing as "have a quick google and give up if I can't find exactly the right code".
从这里开始： Python教程 - Python 3.4.7文档 [ ^ ]。
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