如何格式化日期时间 [英] How to format datetime

问题描述

我需要这种类型的输出

 OutPut：CreatedDate：2017-11-01 11：22：22.931，ActiveOn：2017-11-01 11：22：22.931 

公共类GetActivePro 
 {
 public DateTime CreatedDate {get;组; } 
 public DateTime ActiveOn {get;组; } 
} 

我在我的类中使用dateTime变量，如果我在.ToString（）中转换我的变量，则显示转换错误。

 GetActivePro acpro = new GetActivePro（）; 
 acpro.CreatedDate = DateTime.Now.ToString（yyyy-MM-dd hh：mm：ss tt）

显示错误：

不能隐式地将类型字符串转换为system.datetime 

现在我使用下面的代码，但输出格式不同，



我尝试过：

公共课GetActivePro 
 {
 public DateTime CreatedDate {get;组; } 
 public DateTime ActiveOn {get;组; } 
} 
私有对象GetCustomDate（）
 {
 GetActivePro acpro = new GetActivePro（）; 
 acpro.CreatedDate = DateTime.Now; 
 acpro.ActiveOn = DateTime.Now; 
 
 
返回新
 {
 success = true，
 Acpro = acpro 
}; 
 
} 
 
 OutPut是：CreatedDate：20171101112222931，ActiveOn：20171101112222931 

解决方案

DateTime 不是字符串所以只需：

 acpro.CreatedDate = DateTime.Now; 

如果您需要将DateTime显示为字符串，则转换为字符串：

< pre lang =c＃> string str = acpro.CreatedDate.ToString（ yyyy-MM-dd hh：mm：ss）

DateTime没有格式。它只是一个时刻，从过去的特定日期和时间点开始存储为多个刻度。



你想要做什么将DateTime值设置为格式化字符串：

 public DateTime CreatedDate {get;组; } 

 acpro.CreatedDate = DateTime.Now.ToString（yyyy-MM-dd hh：mm：ss tt）; 

你不能这样做，即使您将字符串解析回DateTime（使用TryParse或TryParseExact），它也不会保留其格式。



您将格式应用于日期时间你准备它输出，你不能在任何其他时间申请它！

 acpro.CreatedDate = DateTime.Now; 

以后再使用ToString显示值。

 const string DTFormat =yyyy-MM-dd hh：mm：ss.fff; 
 
 //样本用法：
 
 //字符串dtformatted = DateTime.Now.ToString（DTFormat）; 
 // Console.WriteLine（DateTime.Now.ToString（DTFormat））; 

I need this type of Output

OutPut: CreatedDate:2017-11-01 11:22:22.931,  ActiveOn:2017-11-01 11:22:22.931

public class GetActivePro
{
	public DateTime CreatedDate { get; set; }
    public DateTime ActiveOn { get; set; }
}

I am using dateTime variable in my class , If I am Converting my variable in .ToString(), it showing conversion error.

GetActivePro acpro = new GetActivePro();
acpro.CreatedDate = DateTime.Now.ToString("yyyy-MM-dd hh:mm:ss tt")

showing error :

cannot implicitly convert type string to system.datetime

Now I am using following code but but output is in different format,

What I have tried:

public class GetActivePro
{
	public DateTime CreatedDate { get; set; }
    public DateTime ActiveOn { get; set; }
}
private object GetCustomDate()
{
	GetActivePro acpro = new GetActivePro();
	acpro.CreatedDate = DateTime.Now;
	acpro.ActiveOn = DateTime.Now;
	

	return new
	{
		success = true,
		Acpro = acpro
	 };

}

OutPut is : CreatedDate:20171101112222931,  ActiveOn:20171101112222931

解决方案

DateTime is not a string so just do:

acpro.CreatedDate = DateTime.Now;

If you need to show the DateTime as a string then to the string conversion:

string str = acpro.CreatedDate.ToString("yyyy-MM-dd hh:mm:ss")

A DateTime doesn't have a format. It's just a "moment in time", which is stored as a number of ticks since a specific date and time point in the past.

What you are trying to do is set a DateTime value to a formatted string:

public DateTime CreatedDate { get; set; }

acpro.CreatedDate = DateTime.Now.ToString("yyyy-MM-dd hh:mm:ss tt");

You can't do that, and even if you parsed the string back to a DateTime (using TryParse or TryParseExact) it would not retain its formatting.

You apply formatting to a Datetime when you prepare it for output, you can't apply it at any other time!

acpro.CreatedDate = DateTime.Now;

And later use the ToString to display the value.

const string DTFormat = "yyyy-MM-dd hh:mm:ss.fff";

// sample usage:

// string dtformatted = DateTime.Now.ToString(DTFormat);
// Console.WriteLine(DateTime.Now.ToString(DTFormat));

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