为什么我不能为我的struct变量赋一个char？ [英] Why can't I assign a char to my struct variable?

问题描述

我正在尝试将单个字符分配给我的结构变量'autocorrect'但它不会让我给我这个错误：



main.c： 134：12：错误：预期的标识符或'（'''之前'。'令牌

Settings.autocorrect ='n';



我不明白为什么。



我的尝试：

I am trying to assign a single char to my structure variable 'autocorrect' but it will not let me and gives me this error:

main.c:134:12: error: expected identifier or ‘(’ before ‘.’ token
Settings.autocorrect ='n';

I don't understand why.

What I have tried:

typedef struct Settings
{
	char* dict_name;
	int max_difference;
	char autocorrect;
}Settings;

if(strstr(str, "autocorrect = yes"))
		{
			Settings.autocorrect = (char*)malloc(sizeof(char));
			Settings.autocorrect = 'y';
		}
		else if(strstr(str, "autocorrect = no"))
		{
			Settings.autocorrect = (char*)malloc(sizeof(char));
			Settings.autocorrect ='n';
		}
	}

推荐答案

设置是一个结构定义，而不是一个可以变量的变量旧数据：您需要创建一个变量来保存一个Settings结构，然后使用它来访问这些字段：

Settings is a struct definition, not a variable that can hold data: you need to create a variable to hold a Settings struct, and then use that to access the fields:

Settings set;
set.autocorrect = 'y';

或

Or

Settings *set = (Settings*) malloc(sizeof(Settings));
set->autocorrect = 'y';

您已将自动更正声明为字符，但您尝试分配 char * 到它。然后，您立即尝试用字符覆盖指针。将您的代码更改为：

You have declared autocorrect as a character and yet you try to assign a char* to it. You then immediately try to overwrite the pointer with a character. Change your code to:

if(strstr(str, "autocorrect = yes"))
    {
        // space is automatically reserved for the character variable.
        Settings.autocorrect = 'y';
    }
    else if(strstr(str, "autocorrect = no"))
    {
        Settings.autocorrect ='n';
    }
}

您不需要为单个字符分配内存。仅适用于以NULL结尾的字符串。

删除

You don'ta need to allocate memory for a single char. Only for a NULL terminated string.
Remove the

malloc()

调用，它将起作用。

这篇关于为什么我不能为我的struct变量赋一个char？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！