有问题的C程序找到2个数字之间的公因数。 [英] Having problem with the C program to find the common factors between 2 numbers.

问题描述

程序不会打印常用的，而是打印初始化值，该值旨在按程序中的编码递增。



我认为问题在于while循环。



如果更正以下代码而不是编写完全不同的代码，将不胜感激。



我尝试了什么：

 ＃ include   <   conio.h  >  
   #include   <   stdio.h  >  
  
  int  main（）{
 
  int  a，b，i，j; 
  int  total_a =  0 ，total_b =  0 ; 
 
 printf（ 输入你的整数：\ n）; 
 scanf（ ％d％d，& a，& b）; 
 
  for （i =  1 ，j =  1 ; i< = a，j< = b; i ++，j ++）{
 
  if （a ％i ==  0 ）
 total_a = total_a *  10  + i; 
 
  if （b％j ==  0 ）
 total_b = total_b *  10  + j; 
 
} 
 
  / *   printf（％d％d ，total_a，total_b）; 
 int total = 0; 
 printf（％d，total）; * /  
 
  int  rem_a，rem_b，total = < span class =code-digit> 0 ; 
 
  while （total_a！=  0 ）{
 
 rem_a = total_a％10; 
 
  while （total_b！=  0 ）{
 
 rem_b = total_b％10; 
 
  if （rem_a == rem_b）{
 total = total *  10  + rem_a; 
} 
 
 total_b / =  10 ; 
} 
 
 total_a / =  10 ; 
} 
 
 printf（ ％d，总计） ; 
 
  return   0 ; 
} 

解决方案

嗯。你需要考虑更多：你的代码没有你想象的那样。

 for（i = 1，j = 1; i< = a， j< = b; i ++，j ++）{

在这个循环中， i 和 j 将始终具有相同的值;他们将从一开始，然后他们都将是两个，依此类推。我不确定他们什么时候会停止，因为我之前没有看过带逗号的情况，我怀疑它会编译 - 我在平板电脑上并且目前没有C编译器我不能检查，但我不认为它是有效的C代码。



可能，你需要一对嵌套的循环，而不是一个循环......

The program doesn't print the common but instead the initialized value which is intended to increment as coded in the program.

And i think the problem lies in the while loop.

it would be appreciated if the following code is corrected instead of writing totally different code.

What I have tried:

#include <conio.h>
#include <stdio.h>

int main(){
	
	int a, b, i, j;
	int total_a=0, total_b=0;
	
	printf("Enter your integers: \n");
	scanf(" %d%d", &a, &b);
	
	for(i=1, j=1; i<=a,j<=b; i++,j++){
		
		if(a%i==0)
			total_a = total_a*10 + i;
			
		if(b%j==0)
			total_b = total_b*10 + j;
		
	}
	
	/*printf(" %d %d", total_a, total_b);
	int total=0;
	printf(" %d", total);*/

	int rem_a, rem_b, total =0;

	while(total_a!=0){
		
		rem_a = total_a%10;
		
		while(total_b!=0){
			
			rem_b =total_b%10;
			
			if(rem_a==rem_b){
				total = total*10 + rem_a;
			}
			
			total_b/=10;
		}
		
		total_a/=10;
	}
	
	printf(" %d", total);
	
	return 0;
}

解决方案

Um. You need to think some more about this: your code doesn't do what you think it will.

for(i=1, j=1; i<=a,j<=b; i++,j++){

Inside this loop, i and j will always have the same value; they will both start at one, then they will both be two, and so on. I'm not sure when they will stop, because I've not seen a condition with a comma in it before and I doubt it will compile - I'm on a tablet and have no C compiler at the moment s I can't check, but I don't think it's valid C code.

Probably, you need a nested pair of loops, rather than a single loop...

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