文件的内容是“我爱计算机”。使用fgets（）读取文件，结果存储在数组buff中。 buff包含什么？ [英] A contents of a file are “I love computerrn”. The file is read using fgets() and the result is stored in array buff. What does buff contain?

问题描述

怎么办这个问题？我不知道答案请帮帮我。



我尝试了什么： < br $>


i不知道答案让我知道。怎么做这个问题？我不知道答案请帮帮我。

how to do this question?I don't know the answer please help me out.

What I have tried:

i don't know the answer let me know.how to do this question?I don't know the answer please help me out.

推荐答案

问题可能不是：文件内容更可能是我喜欢计算机\\\\ n这是非常不同的。



但这是你的作业：所以这是你的任务。

首先查看 fgets的定义： fgets - C ++参考 [ ^ ]很明显，你得到的将取决于你传递给它的参数 - 计数是重要的。如果计数为3，您将在缓冲区中存储四个字符：'I'，''，'l'和'\0' - 最后一个是用于标记字符串结尾的空终止符。其他值将为您提供其他结果...



尝试：查看问题，设置文件，然后编写代码来执行此操作，并使用调试器，以确切了解发生了什么。这并不复杂！

Chances are that the question is not that: the file content is more likely to be "I love computer\r\n" which is very different.

But this is your homework: so it's your task.
Start by looking at the definition of fgets: fgets - C++ Reference[^] and it's obvious that what you get will depend on the parameters you pass to it - the count is significant. If the count is 3, you will get four characters stored in the buffer: 'I', ' ', 'l', and '\0' - the last being a null terminator to mark the end of the string. Other values will give you other results...

Try it: look at the question, set up the file, and write the code to do it, and use the debugger to find out exactly what happens. This isn't complicated!

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