如何使这段代码变得简单 [英] How do I make this code simple

问题描述

您是C编程新手，需要帮助。我想让它变得简单。就像switch语句一样，我希望每个case调用一个函数而不是把整个函数放在那里。但我一直收到错误

Hi new to C programming and need help with something. I'm trying to make it simple. Like for the switch statements I would like for each cases to call on a function instead of putting the whole function there. but I keep getting errors

#include <stdio.h>
#include <stdlib.h>
int
main(void)
{
int user; /*The choice of the user running the program and also what is used for the Switch statements*/
char ch; /*User's answer to run another program or to exit the program. */
	do {
	
	printf("\n\t\t\t\t\t\t\tMENU");
	printf("\n\t\t\t\t\t\t1. Heart Rate Program\n"); /*If user presses 1, Heart Rate Program will Run*/
	printf("\t\t\t\t\t\t2. Leap Year Program\n");   /*Press 2 and Leap Year program will run*/
	printf("\t\t\t\t\t\t3. Chronological Order Program\n");  /*Press 3 and Chronological Order program will run*/
	printf("\t\t\t\t\t\t4. Speed Ticket Program\n"); /*Press 4 and Speed ticket program will run*/
	printf("\t\t\t\t\t\t5.\n");
	printf("\t\t\t\t\t\t6.\n\n");
	printf("\t\t\t\t\t\tEnter your choice: ");
	scanf("%d", &user); /*User picks a number and goes to "user" memory allocation*/
	
	
	/*Switch statement is used to determine which item the user picks and which program to run*/
	switch (user) {
	
		case 1:/*Heart Rate Program*/
			{
				int VALUE, LOWER=80, UPPER=115;
					printf("\n\n\t\t\t\t\t\tHeart Rate:");
					scanf("%d", &VALUE);
						if(VALUE<LOWER)
							printf("\n\t\t\t\t\t\tHeart Rate is LOW\n");
						else if(VALUE>LOWER && VALUE<UPPER)
							printf("\n\t\t\t\t\t\tHeart Rate is OK\n");
						else
							printf("\n\t\t\t\t\t\tHeart Rate is HIGH\n");
			}
			break;
		case 2: /* Leap Year Program*/
			{
				int YEAR;
					printf("\n\n\t\t\t\t\t\tYEAR :");
					scanf("%d", &YEAR);
						if(YEAR%100==0&&YEAR%400==0)
							printf("\n\t\t\t\t\t\t%d is a LEAP YEAR!\n", YEAR);
						else
							printf("\n\t\t\t\t\t\t%d is NOT A LEAP YEAR!\n", YEAR);
			}
			break;
		case 3:/* Chronological Order Program*/
			{
				int FIRST, SECOND, SMALL, LARGE;
					printf("\n\n\t\t\t\t\t\tFIRST :");
					scanf("%d", &FIRST);
					printf("\n\t\t\t\t\t\tSECOND:");
					scanf("%d", &SECOND);
						if(FIRST<SECOND)
							SMALL=FIRST, LARGE=SECOND;
						else if(SECOND<FIRST)
							SMALL=SECOND, LARGE=FIRST;
						else
							return 0;
				printf("\n\t\t\t\t\t\t%d is the smaller number.", SMALL);
				printf("\n\t\t\t\t\t\t%d is the larger number.", LARGE);
				printf("\n\t\t\t\t\t\t%d, %d Ascending Order", SMALL, LARGE);
				printf("\n\t\t\t\t\t\t%d, %d Descending Order\n", LARGE, SMALL);
				
			}
			break;
		case 4: /* Speed Ticket Program*/
			{
				int SPEED=0;
				printf("\n\n\t\t\t\t\t\tSPEED:");
				scanf("%d", &SPEED);
					if(SPEED>=100)
						printf("\n\t\t\t\t\t\tP800 FINE.\n");
					else if(SPEED>=80&&SPEED<100)
						printf("\n\t\t\t\t\t\tP500 FINE.\n");
					else
						printf("\n\t\t\t\t\t\tNO FINE.\n");
			}
			break;
		case 5:
		case 6:
		default :
			printf("\t\t\t\t\t\tInvalid Entry! Please Try Again.\n");
			
		
				}
		printf("\n\n\t\t\t\t\t\tWould you like to try another one? Y/N: ");
		scanf(" %c", &ch);
		system("cls");	
	}
	
	while (ch == 'y' || ch == 'Y');
	
	return (0);
}

我的尝试：



我已经尝试了我在网上看到过的东西，但它告诉我我做错了。

What I have tried:

i've tried what i've seen online but it tells me that i'm doing things wrong.

推荐答案

引用：

我希望每个案例都调用一个函数而不是将整个函数放在那里。但我一直收到错误

I would like for each cases to call on a function instead of putting the whole function there. but I keep getting errors

然后去做。





例如，你可以更换

Then do it.


For instance, you may replace

case 1:/*Heart Rate Program*/
    {
        int VALUE, LOWER=80, UPPER=115;
            printf("\n\n\t\t\t\t\t\tHeart Rate:");
            scanf("%d", &VALUE);
                if(VALUE<LOWER)
                    printf("\n\t\t\t\t\t\tHeart Rate is LOW\n");
                else if(VALUE>LOWER && VALUE<UPPER)
                    printf("\n\t\t\t\t\t\tHeart Rate is OK\n");
                else
                    printf("\n\t\t\t\t\t\tHeart Rate is HIGH\n");
    }
    break;

with

with

case 1:
    heart_rate_fun();
    break;

为您提供

• 声明 heart_rate_fun

void heart_rate_fun();









• 实现（定义） heart_rate_fun 移动相关代码






• implement (define) the heart_rate_fun by moving the relevant code

void heart_rate_fun()
{
  int VALUE, LOWER=80, UPPER=115;
  printf("\n\n\t\t\t\t\t\tHeart Rate:");
  scanf("%d", &VALUE);
  if(VALUE<LOWER)
    printf("\n\t\t\t\t\t\tHeart Rate is LOW\n");
  else if(VALUE>LOWER && VALUE<UPPER)
    printf("\n\t\t\t\t\t\tHeart Rate is OK\n");
  else
   printf("\n\t\t\t\t\t\tHeart Rate is HIGH\n");
}




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