是否有更好，更简单的方法来获得数字列表的正方形和立方体？ [英] Is there is a better and easy way to get a square and cube for list of numbers?

问题描述

输出必须是：

数字方形立方

0 0 0

1 1 1

2 4 8

3 9 27

4 16 64

5 25 125

6 36 216

7 49 343

8 64 512

9 81 729

10 100 1000



我已经尝试过我自己的解决方案，但我认为有更好的方法可以解决这个问题吗？



什么我试过了：

 public class App {
 
 public static void main（String [] args）{
 int n0 = 0; 
 n0 = n0 * n0; 
 int nn0 = 0; 
 nn0 = n0; 
 int n1 = 1; 
 n1 = n1 * n1; 
 int nn1 = 1 * n1; 
 int n2 = 2; 
 n2 = n2 * n2; 
 int nn2 = 2 * n2; 
 int n3 = 3; 
 n3 = n3 * n3; 
 int nn3 = 3 * n3; 
 int n4 = 4; 
 n4 = n4 * n4; 
 int nn4 = 4 * n4; 
 int n5 = 5; 
 n5 = n5 * n5; 
 int nn5 = 5 * n5; 
 int n6 = 6; 
 n6 = n6 * n6; 
 int nn6 = 6 * n6; 
 int n7 = 7; 
 n7 = n7 * n7; 
 int nn7 = 7 * n7; 
 int n8 = 8; 
 n8 = n8 * n8; 
 int nn8 = 8 * n8; 
 int n9 = 9; 
 n9 = n9 * n9; 
 int nn9 = 9 * n9; 
 int n10 = 10; 
 n10 = n10 * n10; 
 int nn10 = 10 * n10; 
 
 System.out.printf（数字方形立方体％n0％d％d％n1％d％d％n2％d％d％n3％d％d％n4％d％d％n5 ％d％d％n6％d％d％n7％d％d％n8％d％d％n9％d％d％n10％d％d，n0，nn0，n1，nn1，n2，nn2，n3， nn3，n4，nn4，n5，nn5，n6，nn6，n7，nn7，n8，nn8，n9，nn9，n10，nn10）; 
 
} 
 
} 

解决方案

是的，还有更好的方法。您可以使用循环，而不是对每个数字进行相同的计算。他们多次重复一段代码。在这里了解它们：

循环 - 学习Java - 免费的交互式Java教程 [ ^ ]

Java循环控制 [ ^ ]



在您阅读完文章之后，我相信用循环重写代码是一个很好的练习:)

the output must be:
number square cube
0 0 0
1 1 1
2 4 8
3 9 27
4 16 64
5 25 125
6 36 216
7 49 343
8 64 512
9 81 729
10 100 1000

and i have tried the solution below by my self, but i think there is a better way to solve this right?

What I have tried:

public class App {

	public static void main(String[] args) {
		int n0 = 0;
		n0 = n0 * n0;
		int nn0 = 0;
		nn0 = n0;
		int n1 = 1;
		n1 = n1 * n1;
		int nn1 = 1*n1;
		int n2 = 2;
		n2 = n2 * n2;
		int nn2 = 2*n2;
		int n3 = 3;
		n3 = n3 * n3;
		int nn3 = 3*n3;
		int n4 = 4;
		n4 = n4 * n4;
		int nn4 = 4*n4;
		int n5 = 5;
		n5 = n5 * n5;
		int nn5 = 5*n5;
		int n6 = 6;
		n6 = n6 * n6;
		int nn6 = 6*n6;
		int n7 = 7;
		n7 = n7 * n7;
		int nn7 = 7*n7;
		int n8 = 8;
		n8 = n8 * n8;
		int nn8 = 8*n8;
		int n9 = 9;
		n9 = n9 * n9;
		int nn9 = 9*n9;
		int n10 = 10;
		n10 = n10 * n10;
		int nn10 = 10*n10;

		System.out.printf("number  square  cube%n0       %d       %d%n1       %d       %d%n2       %d       %d%n3       %d       %d%n4       %d      %d%n5       %d      %d%n6       %d      %d%n7       %d      %d%n8       %d      %d%n9       %d      %d%n10      %d     %d ", n0,nn0, n1,nn1, n2,nn2, n3,nn3, n4,nn4, n5,nn5, n6,nn6, n7,nn7, n8,nn8, n9,nn9, n10,nn10);

	}

}

解决方案

Yes, there is a better way. Rather than doing the same calculations for each number, you can use loops. They repeat a block of code several times. Learn about them here:
Loops - Learn Java - Free Interactive Java Tutorial[^]
Java Loop Control[^]

After you've gone through the articles, I believe it's a good exercise to rewrite your code with loops :)

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